Difficulty: Medium
Correct Answer: 30°
Explanation:
Introduction / Context:
This question examines the relationship between sine and cosine through the complementary angle identity. It also tests the ability to equate angles inside trigonometric functions to find a relationship between x and y. We focus on principal values in a typical aptitude exam setting, avoiding complications from periodicity unless explicitly required.
Given Data / Assumptions:
Concept / Approach:
Use the complementary angle identity cos θ = sin(90° − θ). This allows us to rewrite cos(3y + 20°) as a sine function of a complementary angle. Once both sides are written as sine, we equate the arguments of the sine functions in the simplest principal case. This leads directly to a linear equation in x and y that gives x + y.
Step-by-Step Solution:
Start with sin(3x − 20°) = cos(3y + 20°).Use the identity cos θ = sin(90° − θ). Therefore cos(3y + 20°) = sin(90° − (3y + 20°)) = sin(70° − 3y).Thus the equation becomes sin(3x − 20°) = sin(70° − 3y).For principal values in the range usually used in aptitude exams, we equate the arguments directly: 3x − 20° = 70° − 3y.Rearrange: 3x + 3y = 70° + 20° = 90°, so 3(x + y) = 90°.Therefore x + y = 90° / 3 = 30°.
Verification / Alternative check:
We could consider the more general sine equality sin α = sin β, which has two primary cases: α = β + 360k° or α = 180° − β + 360k°. The principal simple case α = β gives 3x − 20° = 70° − 3y and leads to x + y = 30°. The alternative case would give a more complicated relationship and is usually not intended in standard multiple choice aptitude questions unless specifically mentioned. Checking with sample values that satisfy x + y = 30° confirms that the equation holds for suitable choices of x and y.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
30°
Discussion & Comments