In trigonometry, assume A and B are angles such that: cot A = n/(n + 1) and cot B = 1/(2n + 1). Using the cotangent addition identity, find the value of cot(A + B) in simplest form (as a constant, independent of n, wherever defined).

Introduction / Context:
This question tests the cotangent addition identity and algebraic simplification. The key skill is substituting given cot values and simplifying carefully to see whether the result depends on n or collapses to a constant.

Given Data / Assumptions:

• cot A = n/(n + 1) • cot B = 1/(2n + 1) • Use cot(A + B) identity wherever expressions are defined (denominators not zero)

Concept / Approach:
Use the identity: cot(A + B) = (cot A * cot B − 1) / (cot A + cot B). Substitute the given expressions, convert everything to a common denominator, and simplify. Watch for a common factor that cancels completely.

Step-by-Step Solution:
1) Let u = cot A = n/(n + 1) and v = cot B = 1/(2n + 1) 2) Apply identity: cot(A + B) = (u*v − 1) / (u + v) 3) Compute u*v: u*v = [n/(n + 1)] * [1/(2n + 1)] = n / ((n + 1)(2n + 1)) 4) Numerator: u*v − 1 = [n − (n + 1)(2n + 1)] / ((n + 1)(2n + 1)) 5) Expand (n + 1)(2n + 1) = 2n^2 + 3n + 1 6) So numerator becomes: n − (2n^2 + 3n + 1) = −(2n^2 + 2n + 1) 7) Denominator: u + v = n/(n + 1) + 1/(2n + 1) 8) Common denominator gives: [n(2n + 1) + (n + 1)] / ((n + 1)(2n + 1)) = (2n^2 + 2n + 1) / ((n + 1)(2n + 1)) 9) Divide numerator by denominator: −(2n^2 + 2n + 1)/(2n^2 + 2n + 1) = −1

Verification / Alternative check:
Pick a simple n (for example n = 1): cot A = 1/2 and cot B = 1/3. Then cot(A + B) = ((1/2)(1/3) − 1)/((1/2) + (1/3)) = (1/6 − 1)/(5/6) = (−5/6)/(5/6) = −1. Confirms the constant result.

Why Other Options Are Wrong:
• 0, 1, 2, −2: these would imply the expression depends on n or does not cancel, but the algebra cancels perfectly to −1.

Common Pitfalls:
• Using tan(A + B) identity instead of cot(A + B). • Mistakes in common denominators or expansion of (n + 1)(2n + 1).

Final Answer:
−1