Find the remainder when $(257^{166} - 243^{166})$ is divided by $500$.
Aptitude
Number System
Difficulty: Medium
Choose an option
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A0
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B14
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C243
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D257
Answer
Correct Answer: 0
Explanation
### Concept & Formula
This question relies on standard divisibility rules for algebraic identities. Specifically, for an expression in the form $(x^n - a^n)$, it is always perfectly divisible by $(x + a)$ whenever $n$ is an **even** integer.
### Step-by-Step Solution
**Given:**
Expression: $257^{166} - 243^{166}$
Divisor: $500$
**Calculation / Deduction:**
* Identify the format: The expression matches $x^n - a^n$ where $x = 257$, $a = 243$, and $n = 166$.
* Check the exponent: The power $166$ is an even number.
* Apply the rule: Because the power is even, the expression is perfectly divisible by $(x + a)$.
* Calculate $(x + a)$:
$$ 257 + 243 = 500 $$
* Since the expression is perfectly divisible by $500$, and our given divisor is also $500$, there is no remainder.
### Exam Strategy & Shortcut
Look at the bases and the divisor. $257 + 243 = 500$. This matches the divisor perfectly. Then, look at the sign (minus) and the power (even). By the $(x^n - a^n)$ rule, an even power with a minus sign is divisible by the sum of the bases. Conclude instantly that the remainder is $0$.
### Common Pitfall
A frequent error is confusing the parity rules. Students might mix up $x^n - a^n$ and $x^n + a^n$. Remember:
1. $(x^n - a^n)$ is divisible by $(x - a)$ for ALL $n$.
2. $(x^n - a^n)$ is divisible by $(x + a)$ ONLY for EVEN $n$.
3. $(x^n + a^n)$ is divisible by $(x + a)$ ONLY for ODD $n$.
### Final Answer
Therefore, the correct answer is 0.