If the sum of two numbers is 14 and their difference is 10, find the product of these two numbers.
Aptitude
Number System
Difficulty: Easy
Choose an option
-
A18
-
B20
-
C24
-
D22
Answer
Correct Answer: 24
Explanation
## Concept & Formula
This problem can be solved by translating the wording directly into a system of linear equations.
However, a more advanced and faster approach uses the relationship formula between the sum, difference, and product of two variables:
$$(x + y)^2 - (x - y)^2 = 4xy$$
## Step-by-Step Solution
* **Given Information:** Let the two numbers be $x$ and $y$.
The sum is: $x + y = 14$
The difference is: $x - y = 10$
* **Calculation Method 1: Using the Algebraic Formula**
Plug the known values directly into the identity:
$$(14)^2 - (10)^2 = 4xy$$
$$196 - 100 = 4xy$$
$$96 = 4xy$$
$$xy = \frac{96}{4}$$
$$xy = 24$$
* **Calculation Method 2: Solving for Variables**
* Align the two simple equations:
1) $x + y = 14$
2) $x - y = 10$
* Adding both equations vertically eliminates $y$:
$$2x = 24 \implies x = 12$$
* Substitute $x = 12$ back into the first equation:
$$12 + y = 14 \implies y = 2$$
* Multiply the two numbers together to find the product:
$$12 \times 2 = 24$$
## Exam Strategy & Shortcut
In competitive exams, bypass algebra entirely for "sum and difference" integer questions. Use this rapid mental arithmetic rule:
**Find the larger number:** Add the sum and difference, then halve it. $\frac{14 + 10}{2} = 12$.
**Find the smaller number:** Subtract the difference from the sum, then halve it. $\frac{14 - 10}{2} = 2$.
Multiply them: $12 \times 2 = 24$.
## Common Pitfall
A common error is successfully finding the two numbers ($12$ and $2$) but then accidentally adding them back together or stopping the calculation, completely forgetting that the question specifically asked for their *product*. Always re-read the final sentence of the question before marking your option.
## Final Answer
Therefore, the correct answer is 24.