Evaluate log x + log(1/x) by combining into a single logarithm. State the exact value.

Difficulty: Easy

Correct Answer: 0

Explanation:


Introduction / Context:
We evaluate a basic identity involving a variable and its reciprocal inside logarithms of the same base.


Given Data / Assumptions:

  • x > 0
  • Expression: log x + log(1/x)


Concept / Approach:
Use log A + log B = log(AB). Since x · (1/x) = 1, the expression reduces to log(1).


Step-by-Step Solution:

log x + log(1/x) = log( x · 1/x ) = log(1) = 0


Verification / Alternative check:
Regardless of base (consistent across both logs), log(1) equals 0, so the value is unambiguously 0.


Why Other Options Are Wrong:
1 or −1 would correspond to log(10) or log(0.1) in base 10, but the argument here equals 1; 1/2 is likewise irrelevant.


Common Pitfalls:
Attempting to add arguments rather than multiply (x + 1/x) is a different expression and not applicable here.


Final Answer:
0

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