Directions: Solve the quadratic and answer the following questions. A : $(x-2)^2 = (-3x^2) + 2^2 + 25x - P$ B: $\left(10y^2 - 3^2y + \frac{2}{3}\right) \times 3 + 10y = 0$ One root of equation A is $5$. $\frac{7P}{P - 24} \times 0.2P - 91$ is equal to
Aptitude
Quadratic Equation
Difficulty: Medium
Choose an option
-
AP + 2
-
B2P + 2
-
C2P - 1
-
DP - 1
-
ENone of these
Answer
Correct Answer: P - 1
Explanation
### Concept & Algebraic Substitution
To find the value of the given expression, we must first determine the value of the unknown constant $P$. We can find $P$ by utilizing the fact that $x=5$ is a root of equation A.
$$ ax^2 + bx + c = 0 $$
### Step-by-Step Solution
1. **Simplify Equation A:**
$(x-2)^2 = -3x^2 + 2^2 + 25x - P$
$x^2 - 4x + 4 = -3x^2 + 4 + 25x - P$
Bring all terms to one side:
$4x^2 - 29x + P = 0$
2. **Find the value of $P$:**
Since $x = 5$ is a root, substitute $x = 5$ into the simplified equation:
$4(5)^2 - 29(5) + P = 0$
$100 - 145 + P = 0$
$-45 + P = 0 \implies P = 45$
3. **Evaluate the target expression:**
Substitute $P = 45$ into $\frac{7P}{P - 24} \times 0.2P - 91$:
$= \frac{7(45)}{45 - 24} \times 0.2(45) - 91$
$= \frac{315}{21} \times 9 - 91$
$= 15 \times 9 - 91$
$= 135 - 91 = 44$
4. **Check the options by substituting $P = 45$:**
(a) $P + 2 = 47$
(b) $2P + 2 = 92$
(c) $2P - 1 = 89$
(d) $P - 1 = 44$
The evaluated expression matches option (d).
### Exam Strategy & Shortcut
Whenever a root is given for an equation with a single unknown variable, substituting the root directly is the fastest way to isolate the variable. Simplify expressions early to prevent arithmetic errors with large numbers.
### Common Pitfall
A common mistake is failing to simplify equation A correctly before substitution, particularly forgetting to move the $-3x^2$ over to make it $4x^2$, which will result in an incorrect $P$ value.
### Final Answer
Therefore, the correct answer is **P - 1**.