Difficulty: Easy
Correct Answer: azeotropic distillation
Explanation:
Introduction / Context:
Conventional distillation of fermented beer or mash is limited by the ethanol–water azeotrope near 95–96% v/v at atmospheric pressure. Exceeding this concentration is necessary for fuel-grade ethanol and some industrial uses. This question targets the unit operation needed to surpass the azeotrope.
Given Data / Assumptions:
Concept / Approach:
Azeotropic distillation introduces a third component (entrainer) or exploits pressure-swing to alter relative volatilities and break the ethanol–water azeotrope, allowing purification above 95%. Common industrial alternatives include molecular sieves (adsorption) and pervaporation, but in the context of “distillation” methods, azeotropic distillation is the canonical answer.
Step-by-Step Solution:
Recognize the 95% v/v limit from ordinary fractional distillation.Identify the need for an azeotrope-breaking technique.Select “azeotropic distillation” as the appropriate method among the options.
Verification / Alternative check:
Industrial flowsheets often apply rectification to 92–95% followed by azeotropic distillation or dehydration (e.g., cyclohexane entrainer or newer dehydration technologies).
Why Other Options Are Wrong:
Fractional distillation alone cannot exceed the azeotrope; flash or mere “successive” distillations do not change the azeotropic limit.
Common Pitfalls:
Confusing post-distillation dehydration methods (molecular sieves) with “distillation” per se; nonetheless, among distillation choices, azeotropic distillation is correct.
Final Answer:
azeotropic distillation
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