BJT phase relationship — in a common-collector (emitter-follower) voltage amplifier, the output voltage is in phase with the input voltage. Is this statement correct?
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ACorrect
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BIncorrect
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COnly at midband frequencies
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DOnly if load resistance is infinite
Answer
Correct Answer: Correct
Explanation
Introduction / Context:Different BJT amplifier topologies exhibit different phase relationships between input and output. Recognizing these signatures helps during troubleshooting and when choosing stages for buffering or gain. The common-collector stage (emitter follower) is especially valued as a buffer because of its high input impedance, low output impedance, and non-inverting behavior.
Given Data / Assumptions:
- Topology: common-collector (input at base, output at emitter).
- Small-signal AC operation in the passband.
- Biasing set to linear active region.
Concept / Approach:In a common-collector amplifier, the emitter voltage follows the base voltage minus approximately one diode drop (V_BE) for BJTs. Small-signal changes at the base produce similar-polarity changes at the emitter; therefore, the stage is non-inverting (input and output are in phase). By contrast, the common-emitter stage inverts phase by about 180 degrees for voltage signals.
Step-by-Step Solution:
Recall emitter follower relation → v_out ≈ v_in − V_BE (with small AC swing).Sign of gain → positive, near unity (slightly less than 1).Conclude phase → output in phase with input.Therefore, the statement is correct.Verification / Alternative check:Small-signal hybrid-π models show voltage gain ≈ R_L / (r_e + R_L) which is positive; scope measurements confirm in-phase waveforms within the midband region.
Why Other Options Are Wrong:
- Incorrect: contradicts the well-known non-inverting property of emitter followers.
- “Only midband” or “only infinite load”: while extreme frequency or heavy loading alters magnitude, the sign remains non-inverting within the useful band.
Common Pitfalls:Assuming all transistor amplifiers invert because common-emitter does; overlooking the buffering role of the emitter follower.
Final Answer:Correct — the emitter follower's output is in phase with its input.