Difficulty: Easy
Correct Answer: Incorrect — collector current is beta times the base current (Ic ≈ β * Ib)
Explanation:
Introduction / Context:Understanding how collector current (Ic) relates to base current (Ib) is fundamental to biasing and gain calculations. This relation determines the sizing of bias networks and the feasibility of driving loads with given base-drive capabilities.
Given Data / Assumptions:
Concept / Approach:In forward-active mode, Ic ≈ β * Ib, where β (h_FE) is the DC current gain. Because β is much greater than 1, Ic is far larger than Ib, not “approximately equal.” The emitter current is Ie ≈ Ic + Ib ≈ (β + 1) * Ib. In saturation, the proportionality weakens, but Ic still is not ≈ Ib; rather, V_CE collapses and current is limited by the circuit.
Step-by-Step Solution:
Assume β = 100 as an example.For Ib = 0.5 mA, Ic ≈ 50 mA — clearly not equal.Hence the statement “Ic ≈ Ib” is incorrect for normal operation.Bias networks must supply adequate Ib to support the desired Ic = β * Ib.Verification / Alternative check:Datasheets list h_FE vs Ic, showing substantial ratios well above unity across operating ranges.
Why Other Options Are Wrong:
“Correct” contradicts the very definition of current gain.“Only in saturation”: even there, equality is not the defining relation.Material- or temperature-only claims ignore the governing device physics.Common Pitfalls:Forgetting β variation with Ic and temperature; assuming a fixed β for precision without design margins.
Final Answer:Incorrect — collector current is beta times the base current (Ic ≈ β * Ib)
Discussion & Comments