Difficulty: Medium
Correct Answer: λg = λ0 / sqrt(1 − (λ0/λc)^2)
Explanation:
Introduction:
Inside a hollow waveguide, the phase constant differs from that in free space due to boundary conditions. This leads to a guide wavelength λg that depends on the operating wavelength λ0 and the mode's cutoff wavelength λc. Correctly relating these three quantities is fundamental for component design and measurement.
Given Data / Assumptions:
Concept / Approach:
The axial phase constant is β = (2π/λ0) * sqrt(1 − (λ0/λc)^2). Since λg = 2π/β, direct substitution yields λg = λ0 / sqrt(1 − (λ0/λc)^2). This expression shows two useful limits: as λ0 → λc (approach cutoff), λg → ∞; as λ0 ≪ λc (well above cutoff), λg → λ0.
Step-by-Step Solution:
Verification / Alternative check:
Many handbooks also present an equivalent reciprocal-squared form: 1/λg^2 = 1/λ0^2 − 1/λc^2. Care must be taken with the signs; a mistaken reversal produces non-physical results. The option provided here (λg = λ0 / sqrt(1 − (λ0/λc)^2)) is the most direct expression for λg.
Why Other Options Are Wrong:
Common Pitfalls:
Forgetting that λg ≥ λ0 for a propagating mode and that λg diverges at cutoff; the correct formula must reflect these behaviors.
Final Answer:
λg = λ0 / sqrt(1 − (λ0/λc)^2)
Discussion & Comments