Difficulty: Medium
Correct Answer: 10 GHz
Explanation:
Introduction:
Transferred-electron (Gunn) devices oscillate due to the formation and transit of high-field domains across the active region. A first-order estimate of the oscillation frequency can be made from the transit time, which depends on the electron drift velocity and the device length under operating bias.
Given Data / Assumptions:
Concept / Approach:
In the simple transit-time approximation, one oscillation period corresponds to the time a domain takes to cross the active length. Thus T ≈ L / v_d and f ≈ 1 / T = v_d / L. This quick estimate often aligns with the X-band operation of many practical Gunn oscillators using sub-millimeter active lengths.
Step-by-Step Solution:
Verification / Alternative check:
Typical Gunn oscillators can operate across 5–100 GHz depending on material, field, and length; the calculation is consistent with common X-band designs.
Why Other Options Are Wrong:
Common Pitfalls:
Using f ≈ v_d / (2L) universally; while subharmonic operation can occur in some circuits, the basic domain transit estimate uses v_d / L.
Final Answer:
10 GHz
Discussion & Comments