Circular waveguides and symmetry: Which of the following circular waveguide modes are circularly symmetric (no azimuthal variation)?

Difficulty: Easy

Correct Answer: both (a) and (b)

Explanation:


Introduction:
Modes in circular waveguides are labeled TEmn or TMmn, where the first index m corresponds to azimuthal variations and the second index n corresponds to radial order. Recognizing which modes are circularly symmetric helps in low-loss transmission and mode conversion design.


Given Data / Assumptions:

  • Circular metallic waveguide with air filling.
  • TE0n modes have m = 0 (no dependence on azimuthal angle φ).
  • We are considering TE01 and TE02 specifically.


Concept / Approach:

Azimuthal symmetry means the fields do not vary with φ. In circular guides, m = 0 satisfies this, so any TE0n or TM0n mode is circularly symmetric. Therefore, TE01 and TE02 are both circularly symmetric modes.


Step-by-Step Solution:

Identify the azimuthal index: m = 0 implies circular symmetry.Check modes: TE01 → m = 0, n = 1; TE02 → m = 0, n = 2.Conclude: both choices are circularly symmetric.


Verification / Alternative check:

Field patterns for TE01 and TE02 show concentric rings with no angular variation, confirming circular symmetry useful for certain low-loss TE01 long-haul systems.


Why Other Options Are Wrong:

  • Neither or a single mode only contradict m = 0 symmetry criterion.
  • TM11 only: TM11 has m = 1, hence not circularly symmetric.


Common Pitfalls:

Confusing dominant mode (TE11) with symmetry; dominance relates to cutoff, not azimuthal variation.


Final Answer:

both (a) and (b)

More Questions from Microwave Communication

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion