Brewster angle for parallel (p-) polarization: air (n1 = 1) to paraffin with εr = 3 (n2 = √3). Find θB.
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A0°
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B30°
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C45°
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D60°
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E75°
Answer
Correct Answer: 60°
Explanation
Introduction / Context:The Brewster angle is the angle of incidence at which the reflected component of a parallel (p-) polarized wave is zero at a dielectric interface. It is a fundamental optics and electromagnetics concept used in polarization control and anti-reflection design.
Given Data / Assumptions:
- Incidence from air (n1 = 1) onto paraffin with relative permittivity εr = 3.
- Refractive index of paraffin: n2 = √εr = √3 ≈ 1.732 (assuming μr = 1).
- Parallel polarization (p-pol) and non-magnetic media.
Concept / Approach:
Brewster angle for p-polarization is θB = arctan(n2/n1). With air to dielectric, θB depends only on the refractive index ratio (if μr ≈ 1).
Step-by-Step Solution:
Compute refractive index: n2 = √3 ≈ 1.732.Apply formula: θB = arctan(n2/n1) = arctan(1.732) ≈ 60°.Thus, the Brewster angle is 60°.Verification / Alternative check:
Snell’s law and Fresnel coefficients confirm that for p-polarization, the reflection coefficient goes to zero at θB where transmitted and reflected rays are orthogonal, which occurs at arctan(n2/n1).
Why Other Options Are Wrong:
- 0°, 30°, 45°: do not satisfy arctan(√3) ≈ 60°.
- 75°: too large for n2/n1 = √3; arctan growth is slower than linear.
Common Pitfalls:
- Using s-polarization formula (no Brewster zero for s-pol at dielectric-dielectric).
- Using θB = arctan(n1/n2) (inverted ratio) which would be incorrect for incidence from air to denser medium.
Final Answer:
60°