Difficulty: Easy
Correct Answer: Rs 2150
Explanation:
Introduction / Context: This is a classic percentage and discount question from aptitude tests. It models a real electricity bill situation where a certain percentage is deducted as a rebate or concession, and we must recover the original bill amount from the net amount paid.
Given Data / Assumptions:
Concept / Approach: If a discount of d% is given, the customer pays (100 - d)% of the original amount. Here the customer pays 84% of the bill, because 100% - 16% = 84%. Therefore, 0.84 * B = 1806. We can solve this linear equation to find B.
Step-by-Step Solution: Let B be the original electricity bill. After a 16% deduction, the payable fraction is 84% = 84 / 100 = 0.84. So, 0.84 * B = 1806. Rewrite in fraction form: (84 / 100) * B = 1806. Therefore, B = 1806 * (100 / 84). Simplify 100 / 84 = 25 / 21. So B = 1806 * 25 / 21. First compute 1806 / 21 = 86. Then multiply 86 * 25 = 2150. Hence the original bill was Rs 2150.
Verification / Alternative check: Check by recalculating the discount: 16% of 2150 = (16 / 100) * 2150 = 0.16 * 2150 = 344. Subtract the discount from the original bill: 2150 - 344 = 1806. This matches the given payable amount, confirming the answer.
Why Other Options Are Wrong: Rs 1557, Rs 1593, Rs 2186 and Rs 2250 all give different net amounts when 16% is deducted, not equal to 1806. For example, 16% of 2186 is 349.76, and 2186 - 349.76 is not 1806.
Common Pitfalls: Students sometimes treat 16% as the remaining part instead of the discount, leading to equations like 0.16B = 1806 which is incorrect. Another error is rounding too early or mishandling division by 84. Keeping the fraction form and simplifying step by step usually reduces mistakes.
Final Answer: The original electricity bill was Rs 2150.
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