AC maximum power transfer – Complex-conjugate matching Statement: In an AC circuit, power delivered to the load is maximized at the frequency where the load impedance is the complex conjugate of the source (output) impedance. Is this correct?

Electrical Engineering Circuit Theorems in AC Analysis Difficulty: Easy
Choose an option
  • A
    True
  • B
    False
  • C
    True only for purely resistive sources
  • D
    False; the load must equal the source impedance exactly (not conjugate)

Answer

Correct Answer: True

Explanation

Introduction / Context:Maximum power transfer is a cornerstone in RF, audio, and power electronics. In AC systems with reactance, matching is not just about magnitudes; the phase (reactive part) must be addressed via conjugation. This question confirms the complex-conjugate matching condition for peak power delivery.

Given Data / Assumptions:

  • Linear AC circuit analyzed at a specific frequency using phasors.
  • Source (output) impedance Zs = Rs + jXs, load impedance ZL = RL + jXL.
  • Goal: maximize average power absorbed by the load.

Concept / Approach:

The average power to the load is maximized when ZL = Zs* (the complex conjugate of Zs). This cancels reactive parts (XL = −Xs) and matches resistive parts (RL = Rs), maximizing the magnitude of load voltage/current product that contributes to real power without reactive circulation.

Step-by-Step Solution:

Let Zs = Rs + jXs and ZL = RL + jXL.Power to the load P = |Vth|^2 * RL / |Zs + ZL|^2 (Thevenin form).To maximize P with respect to RL and XL, set XL = −Xs (reactive cancellation).Differentiate P with respect to RL; optimum occurs at RL = Rs.Thus ZL,opt = Rs − jXs = Zs* (complex conjugate).

Verification / Alternative check:

At the match: input seen by source is purely resistive; voltage standing wave ratio is minimized in transmission-line terms, confirming peak power transfer.

Why Other Options Are Wrong:

“False” and “must equal exactly (not conjugate)” ignore reactive cancellation. “True only for resistive sources” is unnecessary; the conjugate form explicitly covers reactive sources.

Common Pitfalls:

Matching magnitudes only; forgetting that reactive parts must cancel to avoid circulating reactive power and suboptimal real power absorption.

Final Answer:

True.

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