Difficulty: Easy
Correct Answer: equal to
Explanation:
Introduction / Context:The Ericsson and Stirling cycles are regenerative cycles composed of isothermal heat transfer processes. With an ideal (perfect) regenerator, both can theoretically achieve the Carnot efficiency when operating between the same high and low temperatures, despite having different process combinations than Carnot.
Given Data / Assumptions:
Concept / Approach:
Carnot efficiency depends only on the two reservoir temperatures: eta_Carnot = 1 − T_L/T_H. An ideal Ericsson cycle, made fully reversible via perfect regeneration, has no net internal temperature differences during heat transfer other than at the reservoirs, making its efficiency depend solely on T_H and T_L, the same as Carnot.
Step-by-Step Solution:
Identify Ericsson sequence: isothermal expansion at T_H, isobaric regeneration cooling, isothermal compression at T_L, isobaric regeneration heating.Assume perfect regenerator so that external heat is added only at T_H and rejected only at T_L.Conclude that the cycle is internally reversible and thus achieves eta = 1 − T_L/T_H.Therefore Ericsson efficiency equals Carnot under these idealizations.Verification / Alternative check:
Derivations using T–s diagrams show equal net area (work) relative to heat in/out purely at isotherms when regeneration is perfect. Any regenerator inefficiency or pressure drop reduces efficiency below Carnot in practice.
Why Other Options Are Wrong:
Greater than Carnot is impossible by the second law. Less than applies when regeneration is imperfect, but the ideal statement specifies perfect regeneration. “Undefined” ignores the specified idealization.
Common Pitfalls:
Confusing Ericsson with Brayton (which has adiabatic legs, not isothermal) and overlooking the crucial role of perfect regeneration.
Final Answer:
equal to
Discussion & Comments