Difficulty: Easy
Correct Answer: F1,6BP does not accumulate markedly; cells primarily perform aerobic respiration
Explanation:
Introduction / Context:Escherichia coli adjusts metabolism depending on oxygen and substrate availability. Under well-aerated conditions, cells preferentially channel carbon through glycolysis and the TCA cycle with oxidative phosphorylation, minimizing overflow metabolites typical of fermentative states. Understanding the behavior of fructose-1,6-bisphosphate (F1,6BP), a key glycolytic intermediate and regulator, clarifies this shift.
Given Data / Assumptions:
Concept / Approach:In the presence of O2, E. coli engages aerobic respiration: pyruvate enters the TCA cycle, and NADH is reoxidized via the respiratory chain, yielding high ATP per mole of glucose. F1,6BP serves as a glycolytic intermediate and allosteric regulator but typically does not accumulate excessively in balanced aerobic growth; large accumulations and overflow (e.g., acetate) are more associated with oxygen limitation or very high glucose feeding that pushes fermentative pathways.
Step-by-Step Solution:
Identify the regime: well-aerated → aerobic respiration favored.Infer metabolite profile: intermediates like F1,6BP remain near steady cellular setpoints; no pathological buildup is expected.Fermentation is suppressed because respiratory NADH reoxidation is efficient with O2 as acceptor.Therefore, choose the statement that indicates no marked accumulation and aerobic respiration dominance.Verification / Alternative check:Chemostat and batch studies show high oxygen transfer correlates with low fermentative by-products (e.g., lactate, ethanol in other organisms, acetate overflow minimized), supporting stable glycolytic intermediates.
Why Other Options Are Wrong:
Common Pitfalls:Assuming that high glucose always causes fermentative overflow; oxygen availability and feed strategy are decisive.
Final Answer:F1,6BP does not accumulate markedly; cells primarily perform aerobic respiration
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