Difficulty: Easy
Correct Answer: average power (true power)
Explanation:
Introduction / Context:
An electrodynamometer wattmeter has a current coil in series with the load and a pressure coil across it. The interaction torque is proportional to the product of instantaneous voltage and current averaged over a cycle. The question asks which power quantity the pointer shows in AC.
Given Data / Assumptions:
Concept / Approach:
Average (real) power in an AC circuit is P = V_rms * I_rms * cosφ. The dynamometer’s average torque is proportional to this P, so its steady reading corresponds to true power. Apparent power S = V_rms * I_rms differs by the power factor and cannot be read directly from a single wattmeter.
Step-by-Step Solution:
Verification / Alternative check:
For a pure inductor (cosφ ≈ 0), the wattmeter reads nearly zero, confirming it measures real—not apparent—power.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
average power (true power)
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