Difficulty: Easy
Correct Answer: Voltmeter with sensitivity of 10 kΩ/V
Explanation:
Introduction / Context:When measuring voltage across a component, the voltmeter should draw negligible current so that the circuit under test is not disturbed. Sensitivity in kΩ/V (for analog meters) indicates the input resistance per volt of range; higher sensitivity means higher input resistance and less loading.
Given Data / Assumptions:
Concept / Approach:
Loading error is minimized when R_meter ≫ R_load. For a sensitivity S (kΩ/V) on a V-range, R_meter = S * V (in kΩ). A 10 kΩ/V meter on, say, a 10 V range has 100 kΩ input—five times the 20 kΩ load—resulting in reasonable accuracy compared to a 1 kΩ/V meter (only 10 kΩ on 10 V range) or a fixed 5 kΩ instrument.
Step-by-Step Solution:
Assume a 10 V range example: R_meter(10 kΩ/V) = 10 * 10 kΩ = 100 kΩ.Parallel of 20 kΩ with 100 kΩ ≈ 16.7 kΩ → only ~16% reduction, acceptable for many purposes.For 1 kΩ/V on 10 V, R_meter = 10 kΩ → heavy loading (effective ≈ 6.7 kΩ).5 kΩ fixed is worse; equal to 20 kΩ is still not “≫”.Verification / Alternative check:
Digital voltmeters typically have 10 MΩ input, giving negligible loading; among the given analog choices, 10 kΩ/V is the best to reduce error.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
Voltmeter with sensitivity of 10 kΩ/V
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