Difficulty: Easy
Correct Answer: phosphoglyceraldehyde; NADPH+H+
Explanation:
Introduction / Context:
The Calvin–Benson cycle fixes CO2 into organic molecules. After carboxylation by RuBisCO, the reduction phase converts 3-phosphoglyceric acid (3-PGA) into triose phosphates that serve as precursors for carbohydrates and other biomolecules. Recognizing the product and reductant is essential for linking photosynthetic light reactions to carbon assimilation.
Given Data / Assumptions:
Concept / Approach:
3-PGA is first phosphorylated by ATP to 1,3-bisphosphoglycerate and then reduced by NADPH + H+ to glyceraldehyde-3-phosphate (phosphoglyceraldehyde). NADPH provides the high-energy electrons derived from photosystem I, directly coupling light energy to CO2 reduction.
Step-by-Step Solution:
Verification / Alternative check:
Textbook stoichiometry for one CO2 fixed requires ATP and NADPH; NADPH specifically supplies the reducing equivalents in chloroplasts and many photoautotrophic bacteria.
Why Other Options Are Wrong:
NADH + H+: typically used in catabolic pathways; Calvin cycle reduction uses NADPH.
Ribulose-1,5-bisphosphate is the CO2 acceptor regenerated later, not the reduction product of 3-PGA.
Pyruvic acid is not a Calvin cycle intermediate.
Common Pitfalls:
Confusing G3P (PGAL) with 3-PGA; mixing up NADH and NADPH roles; forgetting the ATP-dependent phosphorylation preceding the reduction step.
Final Answer:
phosphoglyceraldehyde; NADPH+H+
Discussion & Comments