Difficulty: Easy
Correct Answer: Oxidative phosphorylation
Explanation:
Introduction / Context:Aerobic cellular respiration extracts energy from glucose and other fuels in several stages: glycolysis, pyruvate oxidation, the tricarboxylic acid (TCA) cycle, and the electron transport chain coupled to oxidative phosphorylation. Understanding where most ATP is made is essential for biochemistry and physiology.
Given Data / Assumptions:
Concept / Approach:Oxidative phosphorylation couples electron transport to ATP formation via chemiosmosis. Electron flow through complexes I–IV pumps protons, creating a proton-motive force that powers ATP synthase. This step accounts for the largest fraction of ATP produced per glucose under aerobic conditions.
Step-by-Step Solution:
Estimate ATP from substrate-level steps: glycolysis (2 ATP) + TCA (1 ATP or GTP per turn ×2 ≈ 2 ATP).Account for reduced cofactors: multiple NADH and FADH2 generated feed the electron transport chain.Recognize that ATP synthase uses the proton gradient to synthesize the majority of ATP → oxidative phosphorylation is dominant.Verification / Alternative check:Pharmacologic inhibition (e.g., oligomycin or cyanide) collapses ATP output despite intact glycolysis/TCA, confirming oxidative phosphorylation as the principal ATP source in aerobiosis.
Why Other Options Are Wrong:
Common Pitfalls:Assuming “most ATP” comes from the TCA cycle itself; the cycle mainly provides NADH/FADH2 for oxidative phosphorylation.
Final Answer:Oxidative phosphorylation
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