Micro-hydrodynamics — drag coefficient at very low Reynolds number A bacterium of size 1 µm swims in water at 1 mm/s (kinematic viscosity ν = 1×10^-6 m^2/s). What is the order of magnitude of its drag coefficient?

Difficulty: Medium

Correct Answer: 24000

Explanation:


Introduction / Context:
At microscopic scales, flows are dominated by viscosity (low Reynolds number). The drag coefficient for small particles or organisms scales inversely with Reynolds number in the creeping-flow regime, illustrating why swimming at micro-scales is fundamentally different from macro-scales.


Given Data / Assumptions:

  • Characteristic length L ≈ 1 µm = 1×10^-6 m.
  • Speed V = 1 mm/s = 1×10^-3 m/s.
  • Kinematic viscosity ν = 1×10^-6 m^2/s.
  • Reynolds number Re = V * L / ν.


Concept / Approach:
For very small Re (creeping flow), an approximate relation for bluff-body drag coefficient is Cd ≈ 24/Re (Stokes regime). We compute Re and then estimate Cd order of magnitude.


Step-by-Step Solution:
Compute Re: Re = (1×10^-3 m/s) * (1×10^-6 m) / (1×10^-6 m^2/s) = 1×10^-3.Estimate Cd: Cd ≈ 24 / Re = 24 / (1×10^-3) = 24,000.Round to order of magnitude as required → 24,000.


Verification / Alternative check:
The creeping-flow assumption holds since Re ≪ 1; empirical corrections (Oseen) are minor for this order-of-magnitude question.


Why Other Options Are Wrong:

  • 24: corresponds to Re ≈ 1.
  • 0.44 and 0.24: typical of high-Re streamlined bodies, not micro-swimmers.


Common Pitfalls:

  • Using high-Re intuition; micro-swimmers operate where inertia is negligible.


Final Answer:
24000

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