Clock will make right angle at (5n + 15) x 12/11 min past n.
Given that, n = 3
? Clock will make right angle at ( 5 x 3 + 15 ) x 12/11 min past 3 . =30 x 12 / 11 min past 3.
= 328/11 min
So required time = 3 H 328/11 min
?.04 = ?4/100
= 2/10
= 0.2
If | 144 | = | 14.4 | , then the value of x is: |
0.144 | x |
144 | = | 14.4 |
0.144 | x |
⟹ | 144 x 1000 | = | 14.4 |
144 | x |
⟹ x = | 14.4 | = 0.0144 |
1000 |
As per the given above question , we have
Birth date of Sashikant = September 28
Difference in number of days from August 15 to September 28 = 16 + 28 = 44
Number of odd days in 44 days = 2 odd days
Hence , Birthday of Shashikant = Sunday + 2 odd days = Tuesday.
Required compound ratio = (2 x 5 x 4) / (7 x 3 x 7)
= 40/147
= 40 : 147
Volume = 1989
? lbh = 1989
? 17 x 13 x h = 1989
? h = 1989/(17 x 17) = 9 cm
As per the above given question , we can say that
Number of days from January 25, 1994 to March 2, 1994 is
January + February + March = 6 + 28 + 2 = 36 days = 5 weeks + 1 odd day
? Number of odd days = 1
? Day on January 25, 1994 is one day before the day on March 2, 1994.
But March 2, 1994 was on Wednesday.
Therefore , January 1994 25 was on Tuesday
1600 years of 0 odd days and 30 years have 1 odd day. 49 years contain 12 leap years and 37 ordinary years and therefore (24 + 37) odd days i.e., 5 odd days i.e., 1949 years contain (0 + 1 + 5) = 6 odd days. 26 day of January contain 5 days.Total odd days = (6 + 5) = 11 or 4 days. So, the days was Thursday
Let speed of 1st bus = 5k
and speed of 2nd bus = 3k
According to the question,
5k = 400/8 = 50
? k = 50/5 = 10
? Speed of 2nd bus = 3k = 3 x 10 = 30 km/h
Length of the bridge = Distance travelled by the person in 4 min = Speed x Time
Speed = 54 km/h = 54 x (5/18) = 3 x 5 = 15 m/s
Time = 4 min = 4 x 60 = 240 s
? Required length = 15 x 240 = 3600 m
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