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- Question
- A man performs 2/25 of his total journey by bus, 21/50 by car and the remaining 2 km on foot. Find the total distance covered in the whole journey.?
Options- A. 4 km
- B. 2.7 km
- C. 3.4 km
- D. 3.8 km
- Correct Answer
- 4 km
ExplanationLet total distance covered in the whole journey = L km
? 2L/25 + 21L/50 + 2 = L
? L = 4
? Total distance covered = 4 km - 1. One local and another express train were proceeding in the same direction on parallel tracks at 29 km/h and 65 km/h, respectively. The driver of the former noticed that it took exactly 16 s for the faster train to pass by him. What is the length of the faster train?
Options- A. 60 m
- B. 120 m
- C. 160 m
- D. 240 m Discuss
- 2. The ratio between the speed of Menna and Tenna is 2 : 3. Meena takes 20 min more than Tenna to walk from A to B. If Menna had walked at double the speed, find the time she would take to from A to B.?
Options- A. 30 min
- B. 60 min
- C. 45 min
- D. 110 min Discuss
- 3. The average speed of a train in the onward journey is 25% more than that of the return journey. The train halts for one hour on reaching the destination. The total time taken for the complete to and fro journey is 17 h covering a distance of 800 km. The speed of the train in the onward journey, is?
Options- A. 45 km/h
- B. 47.06 km/h
- C. 50.00 km/h
- D. 56.25 km/h Discuss
- 4. Running at a speed of 60 km/h, a train passed through a 1.5 km long tunnel in 2 min. What is the length of the train?
Options- A. 250 m
- B. 500 m
- C. 1000 m
- D. 1500 m Discuss
- 5. Anurag traveled a distance of 45 km in 8 h 45 min. He traveled partly on foot at 3 km/h and partly by bicycle at 8 km/h .The distance traveled on the bicycle, is?
Options- A. 25 km
- B. 15 km
- C. 30 km
- D. 20 km Discuss
- 6. A man in car notices that he can count 25 telephone posts in 1 min. If they are known to be 40 m apart, then at what speed is the car travelling?
Options- A. 52.4 km/h
- B. 57.6 km/h
- C. 48.2 km/h
- D. 44.9 km/h Discuss
- 7. A man walks 7.5 km at a speed of 3 km/h. At what speed would the man need two walk during the next 2 h to have an average of 4 km/h for the entire session?
Options- A. 3.65 km/h
- B. 4.75 km/h
- C. 5.25 km/h
- D. 6.50 km/h Discuss
- 8. Ram and Sita are walking towards each other with the speed of 8 km/h and 2 km/h, respectively over a road 160 km long. How soon will they meet?
Options- A. 16 h
- B. 8 h
- C. 10 h
- D. 20 h Discuss
- 9. Two train leaves New Delhi at the same time. One travels towards North at 60 km/h and the other travels towards South at 40 km/h . After how many hours will the trains be 150 km apart?
Options- A. 3/2 h
- B. 4/3 h
- C. 3/4 h
- D. 15/2 h Discuss
- 10. Walking 5/7 of his usual rate, a boy reaches his school 6 min late. Find his usual time to reach the school?
Options- A. 10 min
- B. 12 min
- C. 15 min
- D. 18 min Discuss
Time and Distance problems
Search Results
Correct Answer: 160 m
Explanation:
Relative speed of express train to local train = 65 - 29 = 36 km/h
= 36 x (5/18) m/s = 10 m/s
? Length of faster train = 10 x 16 = 160 m
Correct Answer: 30 min
Explanation:
Since, ratio of speeds of Meena and teena is 2 : 3.
? Ratio of time taken = 3 : 2
If, Teena takes x min to walk from A to B, then Meena takes (x + 20) min.
? (x + 20)/x = 3/2 ? 2x + 40 = 3x
? x = 40 min
Hence, Meena takes 60 min walking at her usual speed and at double the speed, she would take 30 min.
Correct Answer: 56.25 km/h
Explanation:
Let the speed of the train during returning journey be x km/h
Speed during onward journey = x + 25x/100 = 5x/4 km/h.
Distance coverd in onward journey = 800 / 2 = 400 km
Total time taken = Covered distance / Speed
Time taken by train in onward journey = 400/(5x/4)
and time taken in returning journey = 400/x
Thus, 400/(5x/4) + 400/x = 16
? 320/x + 400/x = 16
? 16x = 720
? x = 45 km/h
Speed of the train in the onward journey = 5 x 45/4 = 56.25 km/h
Correct Answer: 500 m
Explanation:
Suppose length of the train = L m
Speed of the train = 60 km/h = 60 x 1000 = 60000 m/h
Length of tunnel = 1.5 km = 1500 m
Time taken by train = 2 min = 1/30 h
Time = Distance/Speed
? 1/30 = L + 1500/60000
? l = 500 m
Correct Answer: 30 km
Explanation:
Let the distance traveled on foot be x km
Then, distance converted by bicycle = (45 - x) km
? x/3 + (45 -x) /8 = 83/4 = 35/4
? (8x + 135 - 3x)/24 = 35/4
? 5x + 135 = 210
? 5x = 75
? x = 15
? Distance converted by bicycle = (45 - 15) = 300 km
Correct Answer: 57.6 km/h
Explanation:
Number of gaps between 25 telephone posts = 24
Distance travelled in 1 min = 40 x 24 = 960 m
Speed = (960 x 60)/1000 = 57.6 km/h
Correct Answer: 5.25 km/h
Explanation:
Let speed of walking be V km/h.
Total time taken = (7.5/3) + 2 = 4.5 h
Total distance covered = (7.5 + 2V) km
? (7.5 + 2V)/4.5 = 4
? 7.5 + 2V = 18
? 2V = 10.5
? V = 5.25
? Speed of walking = 5.25 km/h
Correct Answer: 16 h
Explanation:
Distance = 160 km
Relative Speed = 8 + 2 = 10
Time = Distance/Relative speed = 160/10 = 16 h
Correct Answer: 3/2 h
Explanation:
Relative speed = 60 + 40 = 100 km/h
Time = Distance/speed = 150/ 00 = 3/2 h
Correct Answer: 15 min
Explanation:
Since, the boys now walks at 5/7 of usual speed, so he will take 7/5 of his usual time.
? Extra time = (7/5 - 1) x Usual time = 6 min (known)
? 2/5 x Usual time = 6
? Usual time = 15 min
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