Number of regular hours during 4 weeks = 8 x 5 x 4 = 160
Amount paid for regular working hours = 160 x 5 = ? 800
Balance left = (920 - 800) = ? 120
So, ? 120 is paid for his over time at ? 8 per h.
? Total number of overtime working hours = 120/8 = 15 h
Total working hours = (160 + 15) = 175 h
As the efficience of Romil is twice that of Sanjay, Romil, will take x h for completeion of the work, when Sanjay is taking 2x h.
Given, 2x - x = 4
? x = 4
Hence, they take = 1/(1/4 + 1/8) = 8/3 h
(P + Q)'S 1 day's work = 1/6
(Q + R)'s 1 day's work = 1/10
(P + R)'s 1 day's work = 1/5
On adding, 2 (P + Q + R)'s 1 day's work = 1/6 + 1/10 + 1/5 = 7/15
( P + Q + R)'s 1 day's work = 7/30
? (P + Q + R)'s can do the entire work in = 30/7 = 42/7 days
Women's 1 day's work = 1/6
(Women + Daughter)'s 1 day's work = 1/4
? Daughter's 1 day's work = 1/4 - 1/6 = 1/12
So, the daughter can do the work in 12 days.
(A + B + C)' S 1 day's work = (1/24) + (1/6) + (1/12) = 7/24
? (A + B + C) can do the entire work in = 24/7
= 33/7 days
Efficiency of (A + B) = 12.5%
Efficiency of (B + C) = 8.33%
Efficiency of (C + A) = 12.5%
? Efficiency of [(A + B) + (B + C) + (C + A)] = 33.33%
? Efficiency of (A + B + C) = 16.66%
? No. of days Required by A, B and C together = 100/16.66 = 6 days
Net part filed in 1 h = (1/20 + 1/30 - 1/40) = 7/120
Hence, the tank will be full in 120/7 = 171/7 h
Portion of work completed by one man in 11/2 days.
i.e., 3/2 days = 3/(2 x 3) = 1/2
Portion of work completed by one women in 11/2 days.
i.e., 3/2 days = 3/(2 x 4) = 3/8
? Portion of work completed by boys = 1 - (1/2 + 3/8) = 1/8
Now, portion of work completed by each boy in 3/2 days = 3/(2 x 12) = 1/8
Hence, only one boys would be required.
Efficiency of the leak = 1/6
Combined efficiency of leak and inlet pipe
So, efficiency of inlet pipe = 1/6 - 1/8 = (4 - 3)/24 = 1/24
Inlet pipe can fill the tank in 24 h, at rate of 4 L/min.
? Capacity = 24 x 60 x 4 = 5760 L
Work done by A and B in one day = 1/12
Work done by B and C in one day = 1/15
Work done by C and A is one day = 1/20
On adding all these,
2(A + B + C)'s work of one day = 1/12 + 1/15 +1/20 = 1/5
? (A + B + C)'s one day work = 1/10
? A' s one day work = (A + B + C)'s one day work - (B + C )'s one day work
? A's one day work 1/10 - 1/15 = 1/30
Hence, A can do this work in 30 days.
Skill ratio of A and B = 8 : 5
So, the time taken by A and B 5W and 8W, respectively.
According to the question, 1/8W + 1/5W = 1/26
? W = (13 x 26)/40
Now, time taken by B is 8W = 8 x 13 x 26/40
= 673/5 days.
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