12 men =18 women
? 1 man = 18/12 women
? 8 men = 18/12 x 8 = 12 women
Given m1 = 18 M2 = 12 +16 = 28,
D1 , D2 = ? and W1 = W2 = 1
According to the formula
M1D1W2 = M2D2W1
? 18 x14 x1= 28 x D2 x1
? D2 = (18 x 14)/28 = 9 days
Alen's one day's work =1/21
Border's one day's work = 1/42
Alen and Border's two days work(working alternatively) = (1/21) + (1/42) = 1/14
So, Alen and Border do 1/14 work in 2 days
So, they complete the work in 14 x 2 = 28 days.
Work of (A + B + C) in 1 H = 1 / 6
Work done in 2 h = 2/6 = 1/3
Remaining part of the tank = 1 - 1/3 = 2/3
Time taken by A + B to fill this 2/3rd part of the tank = 8 h
A and B together can fill tank in 12 h (i.e., 8 x 3/2).
Now, we have A, B and C together filling the tank in 6 h and A and B together fill tank in 12 h.
Work done by C alone in 1 h = 1/6 - 1/12 = 1/12
Hence, C alone can fill the tank in 12 h.
Efficiency of Sonu = (100/20) = 5%
Rest work = 75%
? Efficiency of Abhijeet = 75/10 = 7.5%
? Combined efficiency of Sonu and Abhijeet = 7.5 + 5 = 12.5%
? Number of days required by Sonu and Abhijeet, to work togethere = 100/12.5 = 8days
Efficiency (X : Y) = 5 : 1
No. of days (X : Y) = 1 : 5
Efficiency of Ajit : Bablu = 3 : 1
No. of days 1 : 3
Given, M1 = 10 D1 = 8, M2 = ? and D2 = 1/2
From M1D1 = M2D2
? 10 x 8 = M2 x 1/2
? M2 = 10 x 8 x 2
? M2 = 160
Given, M1 = 6, M2 = 8 , T1 = 16 h,
and T2 = ?, W1 = W2 = 1
According to the formula.
M1T1W2 = M2T2W1
? 6 x 16 x 1 = 8 x T2 x 1
? T2 = 16 x 6/8 = 2 x 6 = 12 h
Let food stock will be exhausted in x days .
Given, m1 = 120, D1 = 45
M2 = 120 + 30 = 150
and D2 = ?
Then, using M1D1 = M2D2
? 120 x 45 = 150 x D2
? D2 = 120 x 45/120 = 36
Given, M1 = 5, M2 = ?, T1 = 7, T2 = 3,
W1 = 35 and W2 = 65
According to the formula,
M1T1W2 = M2T2W1
? 5 x 7 x 65= M2 x 3 x 35
? M2 = (5 x 7 x 65)/(35 x 3) = 65/3 boys
M1 = 240, D1 = 48, M2 = 160 and D2 = ?
According to the formula,
M1D1 = M2D2
? 240 x 48 = 160 x D2
? D2= (240 x 48)/160 = 72
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