Let the remainder stock be sold at P% profit.
(P - 20) / 30 = ((1 / 4) / (3 / 4))
or (P ? 20) = 30 × (1 / 3)
or P = 20 + 10
P = 30% profit.
According to figure we can find that the ration would be 1 : 7.
Quantity sold at 10% profit = 1 / (1 + 7)× 160 = 20 kgs.
Quantity sold at 6% loss = (160 ? 20) = 140 kgs.
He should mix 30% and 50% in the ratio 5 : 15 or 1 : 3.
( 30% Solution ) / (50% Solution) = 1 / 3 or 1 : 3
Cost price of the mixture = 15 × (100 / 180) = Rs. 25/3 per kg
(Quantity of rice @ Rs. 8 per kg) / (Quantity of rice @ Rs.10 per kg) = (5 / 3) / (1/3) = 1/5
Quantity of rice @ Rs. 10 per kg = 25 × (1/ 5) = 5 kgs.
Using Alligation rule,
(Quantity of cheaper tea) / (Quantity of dearer tea) = (d - m) / (m - c) = 7/3
Therefore, they must be mixed in the ratio of 7 : 3.
Method 1 to solve the equation.
Let us assume the number of liters of the 90% purity solution = A
and the number of liters of the 97% purity solution = B.
According to question,
Since there are 21 liters of the solution,
A + B = 21 ...................... (1)
Since after mixing the two solutions the new mixture has 94% purity,
Concentrate of A + Concentrate of B = Concentrate of (A + B)
A x 90% + B x 94% = (A+ B) x 97%
? A x 90/100 + B x 97/100 = (A + B) x 94/100
? 90A + 97B = (A + B) x 94
? 90A + 97B = 94A + 94B
? 94A + 94B - 90A- 97B = 0
? 4A - 3B = 0 ........................(2)
Multiply the 3 with Equation (1) and add with Equation (2),
3A + 3B + 4A - 3B = 63 + 0
? 7A = 63
? A = 63/7 = 9
Put the value of A in Equation (1) , we will get
9 + B = 21
B = 21 - 9
B = 12
The first solution would be A = 9 liters.
Method 2 to solve the equation.
Hit and trail method.
94% is closer to 97% but barely meaning the mixtures will not be equal parts but will be slightly more of the higher purity. Quickly eliminate A and B. Out of the others 9 is the easy choice. If the other choices were closer to half this wouldn't work.
Average rate of interest = (100 * 750) / (5000 * 3) = 5% per annual
Investment at 3% per annual = 3 / (3 + 2) × 5000 = Rs. 3000 Investment at 8% per annual = 2 / (3 + 2) × 5000 = Rs. 2000
As per figure we can calculate the ration as below.
Number of supervisors / Number of labourers = (10 / 100) = 1/10
Total number of labourers = Total no. of supervisors × 10
= 15 × 10 = 150.
Number of girls / Number of boys = (3 / 2)
Number of girls = (3 / 2) × 4 = 6
Amount of milk left = 80 [1 - (16 / 80)]3 = 80 (4 / 5)3
80 × (64 / 125) = 40.96 liters.
S.P. of 1 kg mixture = Rs. 68.20, Gain % = 10 %
Hence, C.P. of 1 kg mixture = (100 / 110) x 68 20 . = Rs. 62
By the rule of alligation
Hence, required ratio = 3 : 2
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