A shopkeeper has 100 kgs of tea. He sells a part of it at 20% profit and the rest at 5% loss. If his overall profit is 10%, find the quantity for each part.
Correct Answer: 20 kgs
Explanation:
As per figure, we can calculate as below.
Quantity sold at 20% profit = 3 / (3 + 2) × 100 = 60 kgs.
Quantity sold at 5% loss = (100 – 60) = 40 kgs.
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