2A/5 + 40 = 2B/7 + 20 = 9C/17 + 10 = K
Then, A = (5/2) x (K - 40), B = (7/2) x (K - 20), C = (17/9) x (K - 10)
According to the question, A + B + C = 600
? (5/2) x ( K - 40) + (7/2) x (K - 20) + (17/9) x (K - 10) = 600
? 45 x (K - 40 ) + 63 x (K - 20) + 34 x (K - 10) = 10800
? 45K - 1800 + 63K - 1260 + 34K - 340 = 10800
? 142K - 3400 = 10800
? 142K = 10800 + 3400
? 142K = 14200
? K = 14200/142 =100
? B = (7/2) x (K - 20) = (7/2) x (100 - 20)
= (7 x 80)/2 = 7 x 40
= ? 280
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
Subtract 20, 25, 30, 35, 40, 45 from successive numbers. So 0 is wrong.
NA
Each previous number is multiplied by 2.
? 8 m shadow means original height = 12 m
? 1 m shadow means original height = 12/8 m
? 100 m shadow means original height = (12/8) x 100 m
= (6/4) x 100 = 6 x 25 = 150 m
Let 8% of 96 = y of 1/25
? (8 x 96)/100 = y/25
? y = (8 x 96 x 25)/100 = 192
Since the principal is not given, so data is inadequate.
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