Given, A : B = 2 : 3
and B : C = 4 : 5
Then, A : B : C = 8 : 12 : 15
7there4; Share of B = [12/(8 + 12 + 15)] x 7000
= (12 x 7000)/35
= 2400
= ? 2400
Let the quantity be k.
Then, (a + k) / (b + k) = c/d
? (a + k)d = (b + k)c
? ad + dk = bc + ck
? ad - bc = ck - dk
? ad - bc = k(c - d)
? k = (ad - bc) / (c - d)
If three parts be P, Q and R,
then, P/2 = Q/3 = R/5
? P : Q : R = 2 : 3 : 5
? P = (2/10) x 990 = 198
Q = (3/10) x 990 = 297 and
R = (5/10) x 990 = 495
The ratio among A, B, C and D = 1/3 : 1 / 4 : 1/5 : 1/6
On rearranging the ratio = 60/3 : 60/4: 60/5 : 60/6 = 20 : 15 : 12 : 10
So minimum number of pens can be when the common ration is 1.
So minimum number of pen = 20 + 15 + 12 + 10 = 57
Case I Speed = Distance/ Time
Case II Speed = (Distance/2) / (2 x Time) = Distance / (4 x Time)
? Required ratio = 1/4 = 1:4
Speed of truck 640/10 = 64 km/h
Speed of car = 640/8 = 80 km/h
So, the required ratio = 64/80 = 4/5 = 4 : 5
Let A's share = 3N
B's share = 9N
and D's share = 13N
According to the question
7N = 4872
? N = 4872/7 = 696
Share of A and C = 3N + 9N = 12N
= 12 x 696 = ? 8352
Age of A = (3/8) x 56 = 21 yr
Age of B = (5/8) x 56 = 35 yr
Before 7yr, ration of the ages of A and B
= (21 - 7) : (35 - 7)
= 14 : 28
= 1 : 2
Let the age of father = 5k
and the age of son = 2k
According to the question,
5k x 2k = 1000
? 10k2 = 1000
? k2 = 100
? k = ?100 = 10
? Father's age after 10 yr = (5k + 10)
= 5 x 10 + 10
= 60 yr
Let first number is P and second number is Q.
Then, according to the question,
P x 35% = 2 x Q x 75%
? (P x 35)/100 = (2 x Q x 75)/100
? P/Q = (2 x 75)/35 = (2 x 15)/7 = 30/7
? P : Q = 30 : 7
Milk = 85 x (27/34) kg = 135/2 kg = 67.5 kg
Water = 85 x (7/34) kg = 35/2 kg = 17.5 kg
Let Amount of water to be added is x,
? 67.5 / (17.5 + x) = 3/1
? 3 (17.5 + x) = 67.5
? x =5
? Water to be added = 5 kg.
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