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- Question
- In a school the ratio of boy and girls is 4 : 5 When 100 girls leave the school the ratio become 6 : 7. How many boys are there in the school?
Options- A. 1800
- B. 1200
- C. 1000
- D. 1500
- Correct Answer
- 1200
ExplanationLet number of boys = 4N and number of girls = 5N
Accounting to the question
4N / (5N - 100) = 6/7
? 28N = 6 ( 5N - 100 )
? 28N = 30N - 600
? 2N = 600
? N = 600/2 = 300
? Number of boys = 4N = 4 x 300 = 1200 - 1. The total weight of sanjay and suresh is 120 kg. If sanjay weighs 30 kg more than Suresh, then what is the ratio of the weight of suresh to that of sanjay?
Options- A. 0.4
- B. 0.6
- C. 0.3
- D. 0.25 Discuss
- 2. If x/2y = 6/7, then find the value of (x - y) / (x + y) + 14/19?
Options- A. 5
- B. 1
- C. 4
- D. 3 Discuss
- 3. If (a + b ) : (a - b) = 5 : 3, then find ( a 2 + b 2 ) : ( a 2 - b 2 ) .
Options- A. 17 : 15
- B. 25 : 9
- C. 4 : 1
- D. 16 : 1 Discuss
- 4. If A : B = 3 : 4 and B : C = 8 : 9 then find the value of A : B : C?
Options- A. 3 : 4 : 5
- B. 1 : 2 : 3
- C. 7 : 12 : 17
- D. 6 : 8 : 9 Discuss
- 5. Find the compound ratio of 2 : 7, 5 : 3 and 4 : 7?
Options- A. 147 : 40
- B. 40 : 147
- C. 147 : 30
- D. 30 : 147 Discuss
- 6. In a class the number of boys and girls is in the ratio of 4 : 5. If 10 more boys join the class, the ratio of numbers of boys and girls become 6 : 5. How many girls there in the class?
Options- A. 20
- B. 30
- C. 25
- D. Couldn't be determined Discuss
- 7. The total number of student in a school is 8670. If the number of boys in the school is 4545, then what will be the ratio of the total number of boys to the total number of girls in the school?
Options- A. 303 : 275
- B. 275 : 303
- C. 11 : 12
- D. 12 : 11 Discuss
- 8. A truck covers a distance 640 km in 10 h. A car covers the same distance in 8 h. What is the respective ratio of speed of the truck to that of car?
Options- A. 3 : 4
- B. 1 : 2
- C. 4 : 5
- D. None of these Discuss
- 9. A certain distance is covered at a certain speed. If half of this distance is covered in double the time, the ratio of the two speeds is
Options- A. 4 : 1
- B. 1 : 4
- C. 2 : 1
- D. 1 : 2 Discuss
- 10. A person distributes his pens among four friends A, B, C and D in the ratio 1/3 : 1 / 4 : 1/5 : 1/6. What is the minimum number of pens that the person should have?
Options- A. 75
- B. 45
- C. 57
- D. 65 Discuss
Ratio and Proportion problems
Search Results
Correct Answer: 0.6
Explanation:
Given that
Sanjay + Suresh = 120 ...(i)
Sanjay - Suresh = 30 ...(ii)
By adding Eqs (I) and (ii) we get
2 x sanjay = 150
? sanjay = 150/2 = 75 kg
? Weight of Suresh = 75 - 35 = 45 kg
? Suresh : Sanjay = 45 : 75 = 3 : 5 = 3/5 = 0.6
Correct Answer: 1
Explanation:
Given that, x/2y = 6/7
? x/y = 12/7
By componenod dividendo,
(x - y) / (x + y) = (12 - 7) / (12 + 7) = 5/19
? (x - y) / (x + y) + 14 /19 = 5/19 + 14/19 = 19/19 = 1
Correct Answer: 17 : 15
Explanation:
(a + b) / (a - b) = 5/3
? 3a + 3b = 5a - 5b
? 2a = 8b
? a = 4b,
? a/b = 4/1
Now, ( a2 + b2 ) / (a2 - b2 ) = [a2 / (b2+1)] / [a2 / (b2 -1)]
= [( a/b )2 + 1] / [( a/b )2 - 1] = [( 4/1 )2 + 1] / [( 4/1 )2 - 1]
= [16 + 1] / [16 - 1] = 17/15
? ( a2 + b2 ) : ( a2 - b2 ) = 17 : 15
Correct Answer: 6 : 8 : 9
Explanation:
Given that
A : B = 3 : 4 = ( 3 x 2 ) : (4 x 2 ) = 6 : 8
B : C = 8 : 9
? A : B : C = 6 : 8 : 9
As consequent of the first ratio is equal to the antecedent of second ratio.
Correct Answer: 40 : 147
Explanation:
Required compound ratio = (2 x 5 x 4) / (7 x 3 x 7)
= 40/147
= 40 : 147
Correct Answer: 25
Explanation:
Let original number of boys = 4N and number of girls = 5N
According to the question
(4N + 10)/5N = 6/5
? 30N = 20N + 50
? 10N = 50
? N = 50/10 = 5
? Number of girls = 5N = 5 x 5 = 25
Correct Answer: 303 : 275
Explanation:
Total number of student = 8670
Total number of boys = 4545
? Total number of girls = 8670 - 4545 = 4125
? Required ratio = 4545 : 4125 = 303 : 275
Correct Answer: 4 : 5
Explanation:
Speed of truck 640/10 = 64 km/h
Speed of car = 640/8 = 80 km/h
So, the required ratio = 64/80 = 4/5 = 4 : 5
Correct Answer: 1 : 4
Explanation:
Case I Speed = Distance/ Time
Case II Speed = (Distance/2) / (2 x Time) = Distance / (4 x Time)
? Required ratio = 1/4 = 1:4
Correct Answer: 57
Explanation:
The ratio among A, B, C and D = 1/3 : 1 / 4 : 1/5 : 1/6
On rearranging the ratio = 60/3 : 60/4: 60/5 : 60/6 = 20 : 15 : 12 : 10
So minimum number of pens can be when the common ration is 1.
So minimum number of pen = 20 + 15 + 12 + 10 = 57
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