Ratio of wages of 6 men, 8 women and 6 = (6 x 4) : (8 x 3) : (6 x 2) = 24: 24 : 12
= 2 : 2 : 1
? Total money earned by children = Rs. (950 x 1/5)
= Rs. 190
Let the numbers of hens = x and number of cows = y
Then x + y = 48 and 2x + 4y = 140
Solving these equations, we get 2y = 44
? y = 22
So, x = (48 - 22) = 26
? Number of hens = 26.
Their total age = (3 x 20) yeras = 60 years
Let their ages be 3x, 5x and 7x years.
Then 3x + 5x + 7x = 60
? x = 4
? yongest girl is = 3x = 12 years old.
Let son's age 5 years ago = x years.
Then father's age at that time = 5x years.
After 2 years, son's age = (x + 7) years.
After 2 years, father's age = (5x + 5)
? 3(x + 7) = 5x + 7
? x = 7
Father's age now = ( 5x + 5 ) = 40 years
son's age now = (x+5) = 12 years
? Ratio of their present ages = 40 : 12 = 10 : 3
Let their ages be 4x and x years.
? 6x + 5x = 44
? x = 4
So their present ages are 24 years and 20 years
Ratio of their ages after 8 years = 32 : 28 = 8 : 7.
Let their ages be 4x and x years.
? 4x2 = 196
? x2 = 49
? x = 7
Their ages are 28 years and 7 years.
Ratio of their ages be after 5 years = 33 : 12 = 11 : 4.
Let the numbers be 3x and 4x
Then, their L.C.M. = 12x
? 12x = 180
? x = 15
Hence, the first number = 45
Milk = 60 x (2/3) litres =40 litres
Water = (60 - 40) litres = 20 litres
? 40 / (20 + x) = 1/2
? 20 + x = 80
? x = 60
Hence water to be added = 60 litres.
? A : B = 2 : 3, B : C = 2 : 3 and C:D = 2 : 3
? A : B = 8 : 12, B : C = 12 : 18 and C : D = 18 : 27
? A : B : C : D =8 : 12 : 18 : 27
So A's share = Rs. 1300 x ( 8 / 65) = Rs. 160
First glass contains milk = 1/3 and water = 2/3
Second glass contains milk = 1/4 and water = 3/4
? Now tumbler contains water = (3/2 + 3/4) = 17/12
? Ratio of milk and water =7/12 : 17/12 =7 : 17
Let (a/b) = (c/d) = k
Then, a = bk and c = dk.
? (ma + nc) / (mb + nd) = (mbk + ndk) / (mb + nd) = k(mb + nd/mb + nd)
= k = a/b = a : b.
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