In such question we adopt the Required gain %
= [(100 + common gain%)2 / 100 - 100] %
= { (108)2/100 - 100 } % = 16.64%
Let the C.P. be Rs. x
Then 2(69 - x) / 100 = (78 - x) / 100
? 138 - 2x = 78 - x
? x = 60
? C.P. = Rs. 60
Total C.P.of 200 kg of sugar = Rs. (80 x 6.75 + 120 x 8)
= Rs. (500 + 960)
= Rs. 1460
C.P. of 1 kg = Rs. 1460 / 200 = Rs. 7.30
Gain required = 20%
? S.P. of 1 kg = (120% of Rs. 7.30)
= Rs. (120/100) x 7.30
= Rs. 8.76 per kg
Difference between two selling prices = 475 - 451 = Rs. 24
? 6% of C.P. = Rs. 24
Hence, C.P. = Rs. (24 x 100 / 6) = Rs. 400
? (115% of C.P.) - (125% of 90% of C.P.) = 4
? [115/100 - (125 x 90) / (100 x 100)] x CP = 4
? C.P. = Rs. 160
It is clear that (2.5% of C.P. + 7.5% of C.P.) = 100
? C.P. = Rs. 1000
Now, gain = 121/2
So, Required S.P. = 1121/2% of C.P.
= Rs. (225 / 200) x 1000
= Rs. 1125
Let the marked price be Rs. N
? C.P. = (N - 25% of N) = 3N / 4
? S.P. = (3N / 4 + 10% of 3N / 4) = 33N / 40
But, 33N / 40 = 660
? N = 800
Let original price = Rs. 100
Price after first discount = Rs. 90
Price after second discount = Rs. (80 x 90)/100 = Rs. 72
Price after third discount = Rs. (60 x 72)/100 = Rs. 43.20
? Single equivalent discount = (100 - 43.20) = 56.8%
Let the price of be 4x, 5x and 7x rupees.
Then, 7x - 4x = Rs. 60000
? x = 20000
? Required modest price = 5x = Rs. 100000
Price after 1 st discount = 80% of Rs. 160 = Rs. 128
Price after 2nd discount = 90% of Rs. 128 = Rs. 115.20
Let C.P. = Rs. 100
Then marked price = Rs. 120
S.P. = 90% of Rs. 120 = Rs. 108
? Required gain% = {(108 - 100) / 100} x 100% = 8%
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