Suppose that his salary = Rs. 100
House Rent = Rs.10
so, Balance = Rs. 90
Expenditure on education = Rs. (15 x 90) / 100= Rs.13.50
Balance =Rs.76.50
Expenditure on clothes = Rs.(10 x 76.50) / 100 = Rs. 7.65
Balance now = Rs.68.85
If balance is Rs. 68.85, salary =Rs. 100
If balance is Rs. 1377, salary = Rs.(100/68.85) x 1377 = Rs. 2000
? 36% of N = (113 + 85)
? N = (100 x 198) / 36 = 550
? 30% of 180 + N% of 150 = 50% of (180 + 150)
? 54 + (N x 150)/100 = 165
? 3N/2 = 111
? N = (111 x 2) / 3 =74
Let the Hari Lal was having R rupees in beginning.
? R - [40% of R + 25% of R + 15% of R + 5% of R] = 1305
? R - 85% of R = 1305
? 15% of R = 1305
? R = (1305 x 100)/15 = 8700
Let the number of students appearing for examination in the year 1998 in the states A, B and C be 3N, 5N,and 6N respectively.
According to the question, {(3N x 120)/100} / {(6N x 110)/100} = 1/2
Its true for every N so, The data is inadequate.
Number of females = 156800 x 100/80 = 196000
? Number of males = 7/8 x 196000 = 171500
Total population = 196000 + 171500 = 367500
Reduction in consumption = { m / (100 + m)} x 100%
= (25/125) x 100%
= 20%
Let the number of boys = x
then x + 7x/10 = 85
? x = 50
? No. of girls = 85 - 50 = 35
(i) Number of boys playing only badminton =50% of boys
= 50/100 x 50 = 25
(ii) Number of children playing only table tennis
= 40% of total no. of children
= 40/100 x 85 = 34
(iii) Total no. of children playing both badminton and table tennis = 12
Hence, number of girls playing only badminton = 85 - (25 + 34 + 12)
= 85 - 71 = 14.
Clearly, it is given that 40% failed in Hindi, so those who passed in Hindi = (100 - 40)% = 60%
40% = 24 questions.
? Total question = (100/40) x 24 = 60
Suppose N% familes own both a car and a phone, then
percentage of the families owing only a phone = 25 - N
Percentage of the families owing only a car = 15 - N
? (25 - N) +(15 - N) + N + 65 = 100
? N = 5
Percentage of families who have either a car or a phone = (25 - 5) + (15 - 5) + 5 = 35
So, Statement ll is correct.
Now, suppose the total number of families in the town be A.
? (5 x A)/100 = 2000 ? A = 40000
So, Statement lll is also correct.
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