Home » Aptitude » Percentage

A pot is filled with alcohal. 80% of alcohal is replaced by the same quantity of water. This process is done three times. Find the percentage of alcohal in this mixture of alcohal and water.

Correct Answer: 51.2%

Explanation:

Let quantity of alcohal = 1000 L
Quantity of alcohal after 1st process = 80% of 1000 L = 800 L
Quantity of alcohol after 2nd process = 80% of 800 L = 640 L
Quantity of alcohol after 3rd process = 80% of 640 L = 512 L
∴ Required percentage = (512/1000) x 100 = 51.2%


← Previous Question Next Question→

More Questions from Percentage

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion