Value of ? in expression
7^8.9 ÷ (343)^1.7 x (49)^4.8 = 7^? is

Correct Answer: - 1

Explanation:

Given that, a^{2x + 2} = 1
Apply the algebra Law,
p⁰ = 1
? a^{2x + 2} = a⁰
Apply the algebra law
p^X = p^Y then X will be equal to Y. means X = Y;
? 2x + 2 = 0
? x = -2/2 = -1

Correct Answer: 27

Explanation:

? 3^x - 3^{x - 1} = 18
? 3^{x - 1}(3 - 1) = 18
? 3^{x - 1}(2) = 18
? 3^{x - 1} = 18/2
? 3^{x - 1} = 9
? 3^{x - 1} = 3²
Apply the Algebra law,
If a^X = a^Y then X will be equal to Y.
means X = Y;
? x - 1 = 2
? x = 3
Then x^x = (3)³ = 27

Correct Answer: 1

Explanation:

Correct Answer: 9

Explanation:

Correct Answer: 32 a6

Explanation:

Correct Answer: 216

Explanation:

Given, ?10 + ? x = 4
On squaring both sides, we get
10 + ?x = 16
? ?x = 6
Now, cubic on both sides, we get
x = (6)³ = 216

Correct Answer: 4

Explanation:

Given that, (2^{4x 1/2})^? = 256
Apply the law of Fractional Exponents and Laws of Exponents
? (2²)^? = 2⁸
? 2^{2 x ?} = 2⁸
? 2 x ? = 8
? ? = 8/2 = 4

Correct Answer: 1/25

Explanation:

Given that
(0.00032)^2/5 = (32/100000)^2/5
Solve the equation by algebra Law
= (2⁵/10⁵)^2/5
= {(2/10)⁵}^2/5
= (2/10)^5x2/5
= (1/5)² = 1/25

Correct Answer: 10

Explanation:

2^{x - 1} + 2^{x + 1} = 2560
2^{x - 1} + 2^{x - 1 + 2} = 2560
Apply the Law of Algebra
2^{x - 1} + 2^{x - 1} x 2 ² = 2560
? 2^{x - 1} ( 1 + 2² ) = 2560
? 2^{x - 1} = 2560/5 = 512 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2
? 2^{x - 1} = 2⁹
? x - 1 = 9
? x = 9 + 1 = 10

Correct Answer: 10000

Explanation:

Given equation is
(10)²⁰⁰ ÷ (10)¹⁹⁶
Apply the law of Algebra
a^m ÷ aⁿ = a^{m ? n}
= (10)^{200 - 196}
= 10⁴
= 10000