√56 + √56 + √56 + .... ) ÷ 22 =?

Here, Let us Assume ,
p = √56 + √56 + √56 + ...........
⇒ p = √56 + p
Square on both side and solve the above equation.
⇒ p²= 56 + p
⇒ p² - p= 56
⇒ p(p - 1 ) = 56
⇒ p(p - 1 ) = 8 x 7
⇒ Either p = 8 or p - 1 = 7
⇒ So p = 8;
Now given equation in question is
√56 + √56 + √56 + .... ) ÷ 2² = ?
⇒ p ÷ 2² = ?
Put the value of p
⇒ 8 ÷ 2² = ?
⇒ 8 ÷ 4 = ?
⇒ ? = 2;