? MP of one dozen of pairs of socks = ? 80
? SP of one dozen of pairs of socks
=80 x (100 - 10)/100 = 80 x 90/100= ? 72
Hence, required number of pairs of socks
purchased for ? 24 = (12 x 24)/72 = 4
Here, r = 10% and R = 20%
? Required per cent = (r + R)/(100 - r) x 100 %
= [(10 + 20)/(100 - 10)] x 100% = (30 x 100)/90 %
This shows that the marked price of the item is 100/3 % more
than its cost price.
? Marked price of the article = (450 x 400)/300
= ? 600
Let cost price = ? 100
And marked price = 100 + 40 = ? 140
Let required discount be R %.
According to the question,
140 x (100 - R)/100 = 100
? 100 - R = (100 x 100) / 140
? R = 100 - (100 x 100) / 140
= (40 x 100) / 140
= 28.5 % (approx)
Let marked price = ? 100
And selling price = ? 80
In condition of 10% loss the cost price of article = (80 x 100)/90 = ? 800/9
According to the question,
When SP = 95, then
? Required profit percentage = [{95 - (800/9)} / (800/9)] x 100 = 55/8
= 6.9% (approx)
Let the original price of pant and shirt be = ? N.
? Cost price of point and shirt = [N x (100 - 25)]/100 = ? 3N/4
And selling price of shirt and pant = (3N/4) x (100 + 40)/100 = (3N/4) x (140/100)
= ? 21N/20
Hence, required percentage
= [(21N/20 - N)/ N] x 100 % = 100 / 20 % = 5%
Here, r = 50% and r1 = 30%
? Gain per cent = [r(100 - r1)/100] - r1
= [50 x (100 - 30)/100] - 30
= 35 - 30 = 5%
i. Equivalent single discount to 10 % and 10 % = 10 + 10 - (10 x 10)/100 % = 19 %
ii. Equivalent single discount to 12 % and 8 % = 12 + 8 - (12 x 8)/100 = 20 - 0.96 = 19.04 %
iii. Equivalent single discount to 15 % and 5 % = 15 + 5 - (15 x 5)/100 = 20 - 0.75 = 19.25 %
iv. Equivalent single discount to 20 % = 20 % So, the selling price will be minimum under the scheme iv as in this scheme, the discount is maximum .
Let rate of second discount = r %
MP = ? 3200 , SP = ? 2448 ,
r1 = 10 % and r2 = r %
? y = MP x (100 - r1/100) (100 - r2/100)
? 2448 = [3200 x (100 - 10) x (100 - r)] / (100 x 100)
? (2448 x 100 x 100) / (3200 x 90) = 100 - r
? r = 100 - 85 = 15 %
? S.P of the notebook = ?457
? Commission on one notebook = ? (4 x 457)/100
and commission on 10 notebooks = 10 x (4 x 457)/100 = ? 18280
Now,S.P of the pencil box = ? 80
? Commission on 1 pencil box = ? (80 x 20)/100
Commission on 6 pencil boxes = (80 x 20 x 6)/100 = ? 96
Hence ,total commission of 1 day = (182.80 + 96 ) = ? 278.80
Thus, total commission of 2 weeks = 278.80 x 14 = ? 3903.20
Let the cost price of item = ? N
? Marked price of item = N x (100 + 30)/100 = ? 13N/10
Selling price of the item after two successive discount = (13N/10) x[ (100 - 10)/100 x (100 - 10)/100]
= (13N/10) x (90/100) x (90/100) = ? 1053N/1000
Increment in the price of item = [{(1053N/1000) - N} / N] x 100 %
= 53/10 %
= 5.3 %
Single equivalent discount per cent to 25% and 5%
= r1 + r2 - (r1 . r2)/100 %
= 25 + 5 - (25 x 5)/100
= 30 - 1.25
= 28.78 %
? Required difference = [(30 - 28.75) x 2000]/100
= 1.25 x 2000/100 = ? 25
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