Let, the two natural consecutive odd numbers be n and (n + 2)
Now, according to the question,
? n2 + ( n + 2 )2 = 394
? n2 + n2 + 4 + 4n = 394
? 2n2 + 4n - 390= 0
? n2 + 2n - 195 = 0
? n2 + 15n - 13n - 195 = 0
? n( n + 15 ) - 13( n + 15 ) = 0
? ( n + 15 ) ( n - 13 ) = 0
? n = 13 and n ? - 15
? The two natural consecutive odd numbers be 13 and (13 + 2) = 15 .
? the sum of the numbers = 13 + 15 = 28
Quicker Approach:
By mental operation, 132 + 152 = 169 + 225 = 394
? Required sum = 13 + 15 = 28
The favourable cases are (1, 3), (2, 4) , (3, 5), (4, 6) and (1, 4), (2, 5), (3, 6) and their reversed cases like (3, 1), (4, 2), (5, 3)...
Total number of favourable cases = 2 x 7
? Required Probability P(E) = 14/36 = 7/18
Shantanu's 1 day's work = 1/2
Manu's 1 day's work =1/10
Shantanu's share : Manu's share =(1/12) : (1/10)
= (5/60) : (6/60)
= 5 : 6
Cost of coffee powder used in one cup = 20/10 = ? 2
Cost of milk used in one cup = (30/1000) x 200 = ? 6
? Cost of each cup coffee = 2 + 6 = ? 8
To gain 25% profit, sale price of each cup of coffee = 125% of 8 = ? 10
Let the sugar sold at 8% gain = P
? Sugar sold at 18% gain = (1000 - P)
Let CP of sugar = ? Q per kg
Total CP = ? 1000 x Q
? [(108/100) x PQ)] + [(118/100) x (1000 - P) x Q]
= (114/100) x 1000 Q
? 108PQ + 118000Q - 118PQ = 114000Q
? 10P = 4000
? P = 400
? Quantity sold at 18% profit = 1000 - 400 = 600 kg
In each number except 751, the difference of third and first digit is the middle one .
The pattern is 23, 33, 43, 53, 63, 73.
But 100 is not a perfect cube
Pattern is 1st x 2nd = 3rd; 2nd x 3rd = 4th, 3rd x 4th = 5th. But 4th x 5th = 50 x 500 = 25000 ? 5000 = 6th.
Prime numbers 2, 3, 5, 7, 11, 13 have successively been subtracted. So, 100 is wrong. It must be (108 - 11) i.e., 97.
There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22). Increasing by 3 and 5 respectively.
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