Ⅰ. x 2 – 4 = 0 Ⅱ. y 2 + 6y + 9 = 0

According to question ,we have
From equation Ⅰ. x² – 4 = 0
⇒ x = ± 2,
From equation Ⅱ. y² + 6y + 9 = 0
⇒ ( y + 3 )² = 0
⇒ ( y + 3 )( y + 3 ) = 0
⇒ y + 3 = 0 ⇒ y = -3 , -3
Clearly , x > y is required answer .