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- Question
- Nine engines consume 24 metric tonnes of coal, when each is working 8 hours day. How much coal is required for 8 engines, each running 13 hours a day, if 3 engines of former type consume as much as 4 engines of latter type?
Options- A. 20 metric tonnes
- B. 39 metric tonnes
- C. 23 metric tonnes
- D. 26 metric tonnes
- Correct Answer
- 26 metric tonnes
ExplanationLet required amount of coal be y metric tonnes
9 engines consumes 24 metric tonnes of coal in 8 hours a day.
More engines, more amount of coal (direct proportion)
If 3 engines of first type consume 1 unit, then 1 engine will consume 1/3 unit which is its the rate of consumption.
If 4 engines of second type consume 1 unit, then 1 engine will consume 1/4 unit which is its the rate of consumption
More rate of consumption, more amount of coal (direct proportion)
More hours, more amount of coal(direct proportion)
Now we have , 9 × ( 1 / 3 ) × 8 × y = 8 × ( 1 / 4 ) × 13 × 24
? 3 × 8 × y = 8 × 6 × 13
? 3 × y = 6 × 13 ? y = 2 x 13 = 26 metric tonnes - 1. A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:
Options- A. 39
- B. 37
- C. 42
- D. 56 Discuss
- 2. Nine examiners can examine a certain number of answer books in 12 days by working 5 hours a day. How many hours in a day should 4 examiners work to examine twice the number of answer books in 30 days?
Options- A. 9
- B. 11
- C. 13
- D. 17 Discuss
- 3. 10 men, working 6 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days?
Options- A. 4
- B. 3
- C. 6
- D. 8 Discuss
- 4. In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?
Options- A. 56
- B. 45
- C. 30
- D. 27 Discuss
- 5. 'P' men working 'P' hours per day can do 'P' units of a work in 'P' days. How much work can be completed by 'Q' men working 'Q' hours per day in 'Q' days?
Options- A. P2Q2 units
- B. Q3/P2 units
- C. P2Q
- D. Q2P2 units Discuss
- 6. If 40 men can make 30 boxes in 20 days, How many more men are needed to make 60 boxes in 25 days?
Options- A. 20
- B. 24
- C. 27
- D. 28 Discuss
- 7. 2 men and 7 boys can do a piece of work in 14 days; 3 men and 8 boys can do the same in 11 days. Then, 8 men and 6 boys can do three times the amount of this work in.
Options- A. 18
- B. 21
- C. 34
- D. 39 Discuss
- 8. If 20 men can build a wall 56 meters long in 6 days , what length of a similar wall can be built by 35 men in 3 days?
Options- A. 40
- B. 43
- C. 48
- D. 49 Discuss
- 9. A wheel that has 6 cogs is meshed with a larger wheel of 14 cogs. When the smaller wheel has made 21 revolutions, then the number of revolutions made by the larger wheel is:
Options- A. 4
- B. 9
- C. 14
- D. 7 Discuss
- 10. A contractor undertakes to do a piece of work in 40 days. He engages 100 men at the begining and 100 more after 35 days and completes the work in stipulated time.
If he had not engaged the additional men, how many days behind schedule would it be finished?
Options- A. 7
- B. 18
- C. 12
- D. None Discuss
Unitary Method problems
Search Results
Correct Answer: 42
Explanation:
As per the given question ,
Food of 150 men for 45 days = 150 × 45 = 6750 unit
After 10 days , Food of 150 men for 150 × 10 = 1500 unit
And after 10 days remaining men = 150 - 25 = 125
and remaining food = 6750 - 1500 = 5250 unit
Let D be the number of days for which the remaining food .
So, 125 × D = 5250
? D = 5250 /125 = 42 days
Correct Answer: 9
Explanation:
Correct Answer: 6
Explanation:
Correct Answer: 30
Explanation:
Correct Answer: Q3/P2 units
Explanation:
As we know from the given question,
P men working P hours per day in P days can do P units of a work.
1 men working P hours per day in P days can do P / P units of a work.
1 men working 1 hours per day in P days can do P /P x P units of a work.
1 men working 1 hours per day in 1 days can do P /P x P x P units of a work.
Q men working 1 hours per day in 1 days can do P x Q /P x P x P units of a work.
Q men working Q hours per day in 1 days can do P x Q x Q /P x P x P units of a work.
Q men working Q hours per day in Q days can do P x Q x Q x Q/P x P x P units of a work.
Q men working Q hours per day in Q days can do Q3/P2 units of a work.
Correct Answer: 24
Explanation:
Correct Answer: 21
Explanation:
Correct Answer: 49
Explanation:
Correct Answer: 9
Explanation:
Correct Answer: None
Explanation:
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