Discussion
Home ‣ Aptitude ‣ Unitary Method Comments
- Question
- Nine examiners can examine a certain number of answer books in 12 days by working 5 hours a day. How many hours in a day should 4 examiners work to examine twice the number of answer books in 30 days?
Options- A. 9
- B. 11
- C. 13
- D. 17
- Correct Answer
- 9
Explanation
- 1. 10 men, working 6 hours a day can complete a work in 18 days. How many hours a day must 15 men work to complete the work in 12 days?
Options- A. 4
- B. 3
- C. 6
- D. 8 Discuss
- 2. In a camp, there is a meal for 120 men or 200 children. If 150 children have taken the meal, how many men will be catered to with remaining meal?
Options- A. 56
- B. 45
- C. 30
- D. 27 Discuss
- 3. 'P' men working 'P' hours per day can do 'P' units of a work in 'P' days. How much work can be completed by 'Q' men working 'Q' hours per day in 'Q' days?
Options- A. P2Q2 units
- B. Q3/P2 units
- C. P2Q
- D. Q2P2 units Discuss
- 4. A contract is to be completed in 56 days if 104 persons work, each working at 8 hours a day. After 30 days, 25 % of the work is completed. How many additional persons should be deployed so that the work will be completed in the scheduled time, each person now working 9 hours a day.
Options- A. 60
- B. 58
- C. 12
- D. 56 Discuss
- 5. 39 persons can repair a road in 12 days, working 5 hours a day. In how many days will 30 persons, working 6 hours a day, complete the work?
Options- A. 9
- B. 14
- C. 12
- D. 13 Discuss
- 6. A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is:
Options- A. 39
- B. 37
- C. 42
- D. 56 Discuss
- 7. Nine engines consume 24 metric tonnes of coal, when each is working 8 hours day. How much coal is required for 8 engines, each running 13 hours a day, if 3 engines of former type consume as much as 4 engines of latter type?
Options- A. 20 metric tonnes
- B. 39 metric tonnes
- C. 23 metric tonnes
- D. 26 metric tonnes Discuss
- 8. If 40 men can make 30 boxes in 20 days, How many more men are needed to make 60 boxes in 25 days?
Options- A. 20
- B. 24
- C. 27
- D. 28 Discuss
- 9. 2 men and 7 boys can do a piece of work in 14 days; 3 men and 8 boys can do the same in 11 days. Then, 8 men and 6 boys can do three times the amount of this work in.
Options- A. 18
- B. 21
- C. 34
- D. 39 Discuss
- 10. If 20 men can build a wall 56 meters long in 6 days , what length of a similar wall can be built by 35 men in 3 days?
Options- A. 40
- B. 43
- C. 48
- D. 49 Discuss
Unitary Method problems
Search Results
Correct Answer: 6
Explanation:
Correct Answer: 30
Explanation:
Correct Answer: Q3/P2 units
Explanation:
As we know from the given question,
P men working P hours per day in P days can do P units of a work.
1 men working P hours per day in P days can do P / P units of a work.
1 men working 1 hours per day in P days can do P /P x P units of a work.
1 men working 1 hours per day in 1 days can do P /P x P x P units of a work.
Q men working 1 hours per day in 1 days can do P x Q /P x P x P units of a work.
Q men working Q hours per day in 1 days can do P x Q x Q /P x P x P units of a work.
Q men working Q hours per day in Q days can do P x Q x Q x Q/P x P x P units of a work.
Q men working Q hours per day in Q days can do Q3/P2 units of a work.
Correct Answer: 56
Explanation:
According to question ,
Correct Answer: 13
Explanation:
39 persons can repair a road by working 5 hours a day in 12 days.
1 persons can repair a road by working 5 hours a day in 12 x 39 days.
1 persons can repair a road by working 1 hours a day in 12 x 39 x 5 days.
30 persons can repair a road by working 1 hours a day in 12 x 39 x 5 / 30 days.
30 persons can repair a road by working 6 hours a day in 12 x 39 x 5 / 30 x 6 days.
30 persons can repair a road by working 6 hours a day in 2 x 39 x 5 / 30 days.
30 persons can repair a road by working 6 hours a day in 39 x 1 / 3 days.
30 persons can repair a road by working 6 hours a day in 13 days.
Correct Answer: 42
Explanation:
As per the given question ,
Food of 150 men for 45 days = 150 × 45 = 6750 unit
After 10 days , Food of 150 men for 150 × 10 = 1500 unit
And after 10 days remaining men = 150 - 25 = 125
and remaining food = 6750 - 1500 = 5250 unit
Let D be the number of days for which the remaining food .
So, 125 × D = 5250
? D = 5250 /125 = 42 days
Correct Answer: 26 metric tonnes
Explanation:
Let required amount of coal be y metric tonnes
9 engines consumes 24 metric tonnes of coal in 8 hours a day.
More engines, more amount of coal (direct proportion)
If 3 engines of first type consume 1 unit, then 1 engine will consume 1/3 unit which is its the rate of consumption.
If 4 engines of second type consume 1 unit, then 1 engine will consume 1/4 unit which is its the rate of consumption
More rate of consumption, more amount of coal (direct proportion)
More hours, more amount of coal(direct proportion)
Now we have , 9 × ( 1 / 3 ) × 8 × y = 8 × ( 1 / 4 ) × 13 × 24
? 3 × 8 × y = 8 × 6 × 13
? 3 × y = 6 × 13 ? y = 2 x 13 = 26 metric tonnes
Correct Answer: 24
Explanation:
Correct Answer: 21
Explanation:
Correct Answer: 49
Explanation:
Comments
There are no comments.More in Aptitude:
Programming
Copyright ©CuriousTab. All rights reserved.