1 women ? 1/2 man
10 men + 8 women ? 10 men + 4 men = 14 men
4 men + 6 women ? 4 men + 3 men = 7 men
More men, Less days (Indirect proportion) 7 : 14 : : 5 : N
? N = (14 x 5)/7 = 10 days
3 men ? 6 boys
? 1 man ? 2 boys
? 4 men + 4 boys ? 4 men + 2 men = 6 men
? 3 men can do a work in 18 days.
? 1 man can do a work in 18 x 3 days.
? Required number of days = (18 x 3)/6 = 9 days
Let the required number of days be N.
More men, Less days (indirect proportions)
Soldiers 90 : 72
Ratio 9 : 10
N = (72 x 54 x 10)/(90 x 9) = 48 days
? For 50 students, food is sufficient for 45 days.
? For 1 students, food is sufficient for 45 x 50 days.
? For 75 students, food is sufficient for (45 x 50)/75 days i.e., for 30 days .
Let the number of soldiers transferred be N
Now, the food would last for 25 days for (2000 - N) soldiers.
Less men, More days (indirect proportion)
25 : 20 : : 2000 : (2000 - N)
? 2000 - N = (2000 x 20)/25
? 2000 - N = 1600
? N = 2000 - 1600 = 400
Let the required number of flies be N.
More spiders, More flies (Direct proportion)
More time, More flies (Direct proportion)
? 10 x 10 x N = 200 x 200 x 10
? N = (200 x 200 x 10)/(10 x 10) = 4000 flies
1 man can finish the work in (8 x 12) = 96 days
1 woman can finish the work in (4 x 48) = 192 days
1 child can finish the work in (10 x 24) = 240 days
1 man's 1 day's work = 1/96
1 women's 1 day's work = 1/192
1 child's 1 day's work = 1/240
(10 men + 4 women + 10 children)'s 1 day's work = (10/96 + 4/192 + 10/240)
= (5/48 + 1/48 + 1/24)
= (5 + 1 + 2)/48)
= 8/48 = 1/6
Hence, they will finish the work in 6 days.
Work done = 1/3
Remaining work = 1 - (1/3) = 2/3
Let the number of more men to be employed be N.
More work, More men (Direct proportion)
More days, Less men (Indirect proportion)
Work 1/3 : 2/3
Days 25 : 20
? 1/3 x 25 x (20 + N) = 2/3 x 20 x 20
? (20 + N) = 800/25 = 32
? N = 32 - 20 = 12
Work done = 1/3
Remaining work = (1 - 1/3) = 2/3
Let the number of additional men be N. (Direct proportion)
More days, Less men (Indirect proportion)
Work 1/3 : 2/3
Days 50 : 40
? 1/3 x 50 x (40 + N) = 2/3 x 40 x 40
? 5 x (40 + N) = 2 x 40 x 4
? 200 + 5N = 320
? 5N = 320 - 200 = 120
? N = 120/5 = 24
? Required number of men = 24
7 spiders make 7 webs in 7 days.
? 1 spiders make 7 webs in 7 x 7 days.
? 1 spiders make 1 webs in 7 x 7 / 7 days.
? 1 spiders make 1 webs in 7 days.
16 men working 7 hours day can plough a field in 48 days.
1 men working 7 hours day can plough a field in 48 x 16 days.
1 men working 1 hours day can plough a field in 48 x 16 x 7 days.
14 men working 1 hours day can plough a field in 48 x 16 x 7 / 14 days.
14 men working 12 hours day can plough a field in 48 x 16 x 7 / 14 x 12 days.
14 men working 12 hours day can plough a field in 48 x 16 / 2 x 12 days.
14 men working 12 hours day can plough a field in 48 x 4 / 2 x 3 days.
14 men working 12 hours day can plough a field in 48 x 2 / 3 days.
14 men working 12 hours day can plough a field in 16 x 2 = 32 days.
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