Here M1 = 30, D1 = 16,
T1 = 9, M2 = 36 and T2 = 8
By formula, M1D1T1 = M2D2T2
30 x 16 x 9 = 36 x D2 x 8
? D2 = (30 x 16 x 9)/(36 x 8) = 15 days
4th observation i.e., 8 is the median.
47/10000 = .0047
.02 =(2/100) x 100% =2%
Let N / 11 = 233
Then, N = 233 x 11 = 2563
? Missing digit is 5.
121012 = 12 x 10084 + 4
? remainder = 4
We have the important relation, More work, More time (days)
? A piece of work can be done in 6 days.
? Three times of work of same type can be done in 6 x 3
= 18 days
? = 750.0003 ÷ 19.999
? ? ? 750 ÷ 20
? ? ? 375 ? 38
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