Here M1 = 30, D1 = 16,
T1 = 9, M2 = 36 and T2 = 8
By formula, M1D1T1 = M2D2T2
30 x 16 x 9 = 36 x D2 x 8
? D2 = (30 x 16 x 9)/(36 x 8) = 15 days
? 22 men do the work in 16 days.
? 1 man will do the work in 16 x 22 days.
? 32 men will do the job in = (16 x 22)/32 days
? Required number of days = (16 x 22)/32 = 11 days
Let the required length be L m.
More men, More length (Direct proportion)
Less days, Less length (Direct proportion)
Men 20 : 70
Days 6 : 3
? (20 x 6 x L) = (70 x 3 x 56)
? L = (70 x 3 x 56) / (20 x 6) = 98 m
Let the required number of days be N.
Remaining work = 1 - 5/8 = 3/8
Less work, Less days (Direct proportion)
5/8 : 3/8 : : 20 : N
? N = (3/8) x 20 x 8/5
? N = 12 days
? In 2/3h, 1 article is made.
? In 1h, 3/2 article are made.
? In 71/2 = 15/2h, 3/2 x 15/2 = 45/4 article are made.
? Required articles = 45/4 = 112/4
Let the required number of days be N.
Let men, More days (indirect proportion)
8 : 12 : : 24 : N
? N = (12 x 24)/8 = 36 days
? For 1000 men, provision lasts for 48 days.
? For 1 men, provision lasts for (48 x 1000) days.
? For (1000 + 600) men, provision will last for (48 x 1000)/1600 days.
? Required number of days = (48 x 1000)/1600 = 3 x 10 = 30
M1 = 12 H1 = 16, W1 = 33600
M2 = 18, H2 = 12, W2 = ?
By formula, M1H1/W1 = M2H2/W2
(12 x 16)/33600 = (18 x 12)/W2
? W2 = (33600 x 18)/16
? W2 = 2100 x 8
? W2 = 37800
Let the required number of flies be N.
More spiders, More flies (Direct proportion)
More time, More flies (Direct proportion)
? 10 x 10 x N = 200 x 200 x 10
? N = (200 x 200 x 10)/(10 x 10) = 4000 flies
Let the number of soldiers transferred be N
Now, the food would last for 25 days for (2000 - N) soldiers.
Less men, More days (indirect proportion)
25 : 20 : : 2000 : (2000 - N)
? 2000 - N = (2000 x 20)/25
? 2000 - N = 1600
? N = 2000 - 1600 = 400
? For 50 students, food is sufficient for 45 days.
? For 1 students, food is sufficient for 45 x 50 days.
? For 75 students, food is sufficient for (45 x 50)/75 days i.e., for 30 days .
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