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Home ‣ Aptitude ‣ Problems on H.C.F and L.C.M Comments
- Question
- The product of HCF and LCM of 18 and 15 is
Options- A. 120
- B. 150
- C. 175
- D. 270
- Correct Answer
- 270
ExplanationHCF of 18 and 15
18 = 2 x 3 x 3
15 = 3 x 15 = 3
LCM of 18 and 15 = 2 x 3 x 3 x 5 = 90
? Product of HCF and LCM of both numbers = 3 x 90 = 270 - 1. Find the LCM of 2/3, 3/5, 4/7 and 9/13.
Options- A. 36
- B. 1/36
- C. 1/1365
- D. 12/455 Discuss
- 2. Find the LCM of 1/3, 2/9, 5/6 and 4/27.
Options- A. 1/54
- B. 10/27
- C. 20/3
- D. 3/20 Discuss
- 3. What will be the HCF of ( 2 x 3 x 7 x 9 ), ( 2 x 3 x 9 x 11 ) and ( 2 x 3 x 4 x 5 )?
Options- A. 2 x 3 x 7
- B. 2 x 3 x 9
- C. 2 x 3
- D. 2 x 7 x 9 x 11 Discuss
- 4. If there number are 2a, 5a, and 7a, what will be their LCM?
Options- A. 70a
- B. 65a
- C. 75a
- D. 70a3 Discuss
- 5. Find the least number which when divided by 12, 15, 20 and 24 leaves the same remainder 2 in each case?
Options- A. 122
- B. 120
- C. 124
- D. 126 Discuss
- 6. The HCF of two numbers is 15 and their LCM is 225. If one of the numbers is 75, then find the another number.
Options- A. 105
- B. 90
- C. 60
- D. 45 Discuss
- 7. The HCF of three numbers is 23. If they are in the ratio of 1 : 2 : 3, then find the numbers?
Options- A. 69, 15, 22
- B. 23, 46, 69
- C. 25, 31, 41
- D. 23, 21, 35 Discuss
- 8. The HCF and LCM of two numbers m and n are respectively 6 and 210. If m + n = 72, then 1/m + 1/n is equal to
Options- A. 1/35
- B. 3/35
- C. 5/37
- D. 2/35 Discuss
- 9. The ratio of two numbers is 5 : 6 and their LCM is 480, then their HCF is
Options- A. 20
- B. 16
- C. 6
- D. 5 Discuss
- 10. If a number is exactly divisible by 11 and 13, which of the following types the number must be?
Options- A. Divisible by (11 + 13)
- B. Divisible by (13 - 11)
- C. Divisible by (11 x 13)
- D. Divisible by (13 ÷ 11) Discuss
Problems on H.C.F and L.C.M
Search Results
Correct Answer: 36
Explanation:
Required LCM = (LCM of 2, 3, 4, 9) / (HCF of 3, 5, 7, 13)
= (4 x 9)/1
= 36
Correct Answer: 20/3
Explanation:
We known that,
LCM of fractions = (LCM of numerators) / (HCF of denominators)
? Required LCM = (LCM of 1, 2, 5, and 4) / (HCF of 3, 9, 6 and 27)
? = 20/3
Correct Answer: 2 x 3
Explanation:
Given factors
2 x 3 x 7 x 9; 2 x 3 x 9 x 11; 2 x 3 x 4 x 5
? Required HCF = Product of common prime factors having least powers = 2 x 3
Correct Answer: 70a
Explanation:
Required LCM = a x 2 x 5 x 7 = 70a
Correct Answer: 122
Explanation:
Required number = LCM of (12, 15, 20, 24) + 2
= 120 + 2 = 122
Correct Answer: 45
Explanation:
Let the other number = N
Product of LCM and HCF = Product of two numbers
Then, N x 75 = 15 x 225
? N = (15 x 225)/75 = 45
Correct Answer: 23, 46, 69
Explanation:
Let the numbers are N, 2N and 3N.
Where, N = HCF
Given that, N = 23
? The numbers are 23, 46 and 69.
Correct Answer: 2/35
Explanation:
We have, m x n = 6 x 210 = 1260
? 1/m + 1/n = (m + n)/mn = 72/1260 = 4/70 = 2/35
Correct Answer: 16
Explanation:
Let numbers are 5N and 6N.
Now, HCF of these two numbers is N.
We know that,
LCM x HCF = Product of two numbers
? 480 x N = 5N x 6N
? 480N = 30N2
? N =16
Correct Answer: Divisible by (11 x 13)
Explanation:
LCM of 11 and 13 will be (11 x 13). Hence, if a number is exactly divisible by 11 x 13, then the same number must be exactly divisible by their LCM or by (11 x 13).
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