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The least number which when divided by 12,16 and 18 leaves 5 as remainder in each case. Find the number.

Correct Answer: 149

Explanation:

Given, a = 12, b =16 , c =18, k = 5
According to the formula,
Required number =(LCM of a, b and c) + k
= (LCM Of 12, 16, 18) + 5
LCM of 12, 16, 18 is
∴ LCM = 2 x 2 x 3 x 4 x 3 = 144
∴ Required number =144 + 5 = 149

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