Difficulty: Easy
Correct Answer: 1154
Explanation:
Introduction / Context:
Many olympiad-style and aptitude questions rely on the chain of identities connecting x + 1/x to higher-power symmetric sums. Mastering these shortcuts saves time and prevents arithmetic mishaps.
Given Data / Assumptions:
Concept / Approach:
First find x^2 + 1/x^2 from (x + 1/x)^2 − 2. Then use the identity (x^2 + 1/x^2)^2 = x^4 + 1/x^4 + 2 to reach the target without expanding powers directly.
Step-by-Step Solution:
x^2 + 1/x^2 = (x + 1/x)^2 − 2 = 6^2 − 2 = 36 − 2 = 34.Then x^4 + 1/x^4 = (x^2 + 1/x^2)^2 − 2 = 34^2 − 2 = 1156 − 2 = 1154.
Verification / Alternative check:
Using the recurrence S_n = (x + 1/x)S_{n−1} − S_{n−2}, with S_1 = 6 and S_2 = 34, gives S_4 = 6*(6*34 − 6) − 34 = 6*(204 − 6) − 34 = 6*198 − 34 = 1188 − 34 = 1154, confirming the result.
Why Other Options Are Wrong:
Common Pitfalls:
Expanding x^4 directly; dropping the constant 2 when applying (x^2 + 1/x^2)^2 = x^4 + 1/x^4 + 2.
Final Answer:
1154
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