If x/y =3/4, then the value of [6/7 + (y - x) / (y + x)] equals?

Let 62976/N = 123
Then N = 62976 / 123 = 512.

Let 4050/?N = 450
Then ?N = 4050/450 = 9
? N = (9 x 9) = 81.

Let √N/19 = 4
Then √N = 19 x 4 = 76
∴ N = 76 x 76 = 5776.

Let the number be N.
According to the question,
(N x 3)/2 - N / (3/2) = 10
? 3N/2 - 2N/3 = 10
? (9N - 4N) / 6 = 10
? 5N / 6 = 10
? N = (10 x 6)/5 = 12

The number of pieces of chocolate left with Manju
= 1- [(1/4) + (1/3) + (1/6)
= 1 - (3 + 4 + 2)/12
= 1 - 9/12 = (12 - 9) / 12
= 3/12

Let the number be N.
According to the question,
N - (N x 3/4) =163
? N/4 =163
? N=652

Let the positive number be N.
According to the question,
N + 10 = 200 / N
? N² + 10N = 200
? N² +10N - 200 =0
? (N - 10)(N + 20) = 0
? N = 10 & N= -20
But N not equal to -20 since N is a positive number
So, the required number is 10

Total share given by the person = (1/4) + (1/2) + (1/5)
= (5 + 10 + 4) / 20
=19/20

Let the number be a and b Then
a + b = 10 ..........(i)
ab = 20 ........(ii)

Sum of reciprocal = 1/a + 1/b
= (a + b) / ab
= 10/20
= 1/2

the number of pieces of chocolate left with manju =1- [(1/4) + (1/3) + (1/6)]
= 1 - [ (3 + 4 + 2)/12)
= 1 - (9/12)
= 3/12
Hence number of piece of chocolate left with in manju is 3