How many factors does 120 contains?

Factors of composite number = (P₁ +1)(P₂+1)(P₃+1)......(P_n+1).
Where P₁,P₂,P₃... P_n are the powers of respective prime factors.
So,
120= 2³ x 3¹ x 5¹
Factors=(3+1)(1+1)(1+1)=16.