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Home ‣ Biochemical Engineering ‣ Enzymes and Kinetics Comments
- Question
Lock and key theory is based on the compatibility of
Options- A. enzyme and substrate
- B. enzyme and product
- C. enzyme and enzyme substrate complex
- D. enzyme substrate complex and product
- Correct Answer
- enzyme and substrate
- 1. Classical noncompetitive inhibition is obtained only under
Options- A. slow equilibrium conditions
- B. moderate equilibrium conditions
- C. rapid equilibrium conditions
- D. non-equilibrium conditions Discuss
- 2. Enzymes are basically
Options- A. proteins
- B. vitamins
- C. fat
- D. carbohydrates Discuss
- 3. The active site of an enzyme differs from an antibody-antigen binding site in that the enzyme active site
Options- A. contains modified amino acids
- B. catalyzes a chemical reaction
- C. is complementary to a specific ligand
- D. contains amino acids without side chains Discuss
- 4. The initial velocity, V0, of an enzyme catalyzed reaction reaches Vmax as
Options- A. [S] = KM
- B. [S] = 10 * KM
- C. 1/[S] = 1/KM
- D. 1/[S] ? 0 Discuss
- 5. The rate equation in non-competitive inhibition based on Michaelis Menten equation is given by
Options- A. rmaxS/(Km + S)(1+I/Ki)
- B. rmaxE/(Km (1+I/Ki)+S))
- C. VmaxS/(Km + S)(1+I/Ki)
- D. rmaxS/Km Discuss
- 6. Michaelis Menten equation can also be written as
Options- A. (-Cs)/r = (Cs/rmax)+(Km/rmax)
- B. 1/r = (1/rmax)+(Km/(rmax.Cs))
- C. r = rmax-(Km.r/Cs)
- D. All of these Discuss
- 7. The rate equation in competitive inhibition based on Michaelis Menten equation is given by
Options- A. rmaxS/(Km (1+I/Ki)+S))
- B. rmaxE/(Km (1+I/Ki)+S))
- C. rmaxI/(Km (1+I/Ki)+S))
- D. rmaxS/(Km (1+I/Ki)) Discuss
- 8. Lag phase occurs mainly due to
Options- A. acclimatization with new environment and substrate
- B. higher growth temperature
- C. substrate disliking
- D. variation in substrate concentration Discuss
- 9. The relatively large volume (10 to 40% of total fermenter volume) of the seed culture is employed to
Options- A. increase the overall fermentation time
- B. increase the overall yield of biomass
- C. decrease the overall fermentation time
- D. decrease the overall yield of product Discuss
- 10. In an airlift bioreactor, the air sparging region is called
Options- A. downcomer
- B. disengagement zone
- C. air riser
- D. none of these Discuss
Enzymes and Kinetics problems
Search Results
Correct Answer: rapid equilibrium conditions
Correct Answer: proteins
Correct Answer: catalyzes a chemical reaction
Correct Answer: 1/[S] ? 0
Correct Answer: rmaxS/(Km + S)(1+I/Ki)
Correct Answer: All of these
Correct Answer: rmaxS/(Km (1+I/Ki)+S))
Correct Answer: acclimatization with new environment and substrate
Correct Answer: decrease the overall fermentation time
Correct Answer: air riser
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